Question

How many microliters of original sample are required to produce a final dilution of 10-3 in a total volume of 1,000 mL?

Answer 1

Answer:

$10^{9}\ \mu L$

Explanation:

Considering

$Molarity_{1}\times Volume_{1}=Molarity_{2}\times Volume_{2}$

Given  that:

$Molarity_{1}=1.0\ M$  (let)

$Volume_{1}=1000\ mL$

$Volume_{2}=?$

$Molarity_{2}=0.001\ M$

So,  

$1.0\times 1000=0.001\times Volume_{2}$

Volume = 10⁶ mL

$1\ mL=10^{3}\ \mu L$

So, Volume = $10^{9}\ \mu L$