Answer:
Economic.
Explanation:
In the following scenario, In Quincy, WA, a community that formerly would have a community of 3,500, they are developing new infrastructure. In addition to such friends and neighbors, Quincy citizens will also be seeing more traffic signals, a shopping center, rising property prices, and new opportunities.
So, the following scenario is best suited for the economic changes.
Answer; Electric Paper Display
Explanation:
<em>"PDs are extremely thin and only require power when a new image is requested. Instead of a traditional display that uses backlighting to illuminate pixels, an EPD is based on the scientific phenomena known as "electrophoresis," the movement of electrically charged molecules in an electric field."</em>
Above is the definition, as you can see it resembles your question greatly so this is most likely the answer you're looking for.
Good luck :D
Answer:
var birthday = "12/2/1978";
Explanation:
It does not create a date object named birthday because in this statement the birthday is a string which contains 12/2/1978 a date it is not date object it is a string.All other three options are correct way to create a date object.
var birthday = new Date();
creates a date object with the current date and time.
we can also pass date string in the new Date().So var birthday = new Date("12/2/1978"); is also correct.
we can also pass year,month,day in new Date() In this order only.So option fourth is also correct.
<span>#include <iostream>
using namespace std;
bool bears(int n);
int main(){
int number;
do{
cout<<"enter the amount of bears (press 0 to stop the program): ";
cin>>number;
if (bears(number)){
cout<<"you have reached the goal!"<<endl;
}
else{
cout<<"sorry, you have not reached the goal."<<endl;
}
}while(number != 0);
}
bool bears(int n){
if (n < 42){
return false;
}
else if (n == 42){
return true;
}
else{
if (n % 5 == 0){
return bears(n - 42);
}
else if(n % 2 == 0){
return bears(n / 2);
}
else if(n % 4 == 0|| n % 3 == 0)
{
int one;
int two;
one=n%10;
two=(n%100)/10;
return bears(n - one * two);
}
}
<span>}</span></span>
