1/4 # hamburger = 16 oz to a pound so 1/4 is 4 oz.

1 doz baseballs (12), 5 oz each

Box = 9 oz.

Total weight = 12x5 = 60 oz. + 9 oz. = 69 oz.

69/16 = 4 lb. 5 oz.

5 0

3 years ago

Rick serves his community as a firefighter. he works for a full 24 hours and then is off for the next 48 hours before his next 2

Mrac [35]

Answer: D. $24.30

Step-by-step explanation:

I'm not completely sure.

7 0

3 years ago

Read 2 more answers

The population of a species of rabbit triples every year. This

jok3333 [9.3K]

Answer:

"4" represents that there are 4 rabbit in the beginning.

Step-by-step explanation:

Given that the population of a species of rabbit triples every year. This

can be modeled by function $f\left(x\right)=4\left(3\right)^x$ and $f(5) = 972$ .

Now we need to find about what does the 4 represent in the given function.

We know that exponential function is given by $f\left(x\right)=a\left(b\right)^x$ . Where "a" represents the initial amount.

we have a=4 in given function $f\left(x\right)=4\left(3\right)^x$ .

So that means "4" represents that there are 4 rabbit in the beginning.

3 0

3 years ago

12.what is the probability that a boy and a girl chosen randsomly will be seniors?

zhenek [66]

$\frac{\textbf{1}}{\textbf{20}}$

Step-by-step explanation:

Probability= $\frac{\text{number of favourable outcomes}}{\text{total number of outcomes}}$

Probability for a randomly chosen girl to be senior= $\frac{\text{number of senior girls}}{\text{total number of girls}}$

Probability for a randomly chosen girl to be senior= $\frac{7}{8+11+9+7}=\frac{7}{35}=\frac{1}{5}$

Probability for a randomly chosen boy to be senior= $\frac{\text{number of senior boys}}{\text{total number of boys}}$

Probability for a randomly chosen girl to be senior= $\frac{9}{10+7+10+9}=\frac{9}{36}=\frac{1}{4}$

For two independent events,

Probability for both event 1 and event 2 to take place= $\text{probability of event 1} \times \text{probability of event 2}$

Since choosing boys and girls is independent,

Probability for both boy an girl chosen to be senior= $\text{probability for boy to be senior}\times\text{probability for girl to be senior}$

Probability for both boy and girl chosen to be senior= $\frac{1}{5} \times \frac{1}{4} = \frac{1}{20}$

So,required probability is $\frac{1}{20}$

3 0

3 years ago