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Virty [35]
3 years ago
8

In ΔPQR, point C is the centroid. If PZ = 7, then RZ = A) 3.5 B) 7 C) 14 D) 21

Mathematics
1 answer:
kvv77 [185]3 years ago
4 0

Answer: It's 7

Step-by-step explanation:

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Assign two variables for each problem, and write the equations. Solve.
Elza [17]
Lets make k equal to Kate's age and j equal to Joey's age.  If in 5 years Kate will be twice as old as Joe, you can write the equation k+5=2(j+5) and then simplify it to make it easier to work with.
k+5=2(j+5)
k+5=2j+10
k+5-2j=10
k-2j=5
since we know that right know Kate is 11 years older than Joey, you can write the equation k+j=11.  Since you know have two equations with with the same variable, you can make a system of equations as fallows:
k-2j=5
k+j=11

Since you need to figure out how old Joey is, you need to somehow get k to cancel out.  The easiest thing to do for this problem is to is multiply the top equation by -1 to get:
-k+2j=-5   (you have to add the bottom equation to the top equation)
k+j=11     (-k+k=0, 2j+j=3j, and -5+11=6)
Since k got canceled out, you are left with the equation 3j=6 which means j=2.
Therefore, Joey's current age is 2.

I hope this helps.
7 0
3 years ago
Which expression is a factor of the expression 20c3+540y3​
True [87]

factor 20 out of 20cx*3 =540y*3

so you get 20(cx*3=540y*3) if that is what you are looking for

5 0
2 years ago
X^2+y^2-10x-16y+53=0<br> What is the center of the circle?<br> What is the radius of the circle?
Anon25 [30]

Answer:

Step-by-step explanation:

hello :    Completing The Square

X²+y²-10x-16y+53=0 means : (x²-10x+25-25)+(y²-16y+16-16)+53 =0

(x²-10x+25)-25)+(y²-16y+64)-64+53 =0

(x+5)²+(y-8)² -25-64+53=0

(x+5)²+(y-4)² = 6²  standard form

the center is (-5 , 4) and the radius : 6

7 0
3 years ago
Write the equation of the line that passes through (2, 4) and has a slope of -1 in point-slope form.
Delvig [45]

Answer:

Step-by-step explanation:

y - 4 = -(x - 2)

y - 4 =-x + 2

y = -x + 6

3 0
3 years ago
IF P(A)=1/3, P(B)=2/5, and P(AuB)=3/5, what is P(A^B)?
Bumek [7]

The probability of the union of two events is the sum of their probability, minus the probability of their interserction:

P(A \cup B) = P(A) + P(B) - P(A \cap B)

If we plug the known values into this formula, we have

\dfrac{3}{5} = \dfrac{1}{3} + \dfrac{2}{5} - P(A\cap B)

From which we can deduce

P(A\cap B) = \dfrac{1}{3} + \dfrac{2}{5} - \dfrac{3}{5} = \dfrac{2}{15}

So, the probability of A \setminus B is a bit less than P(A), we have to take away all events that belong to B as well:

P(A \setminus B) = P(A) - P(A\cap B) = \dfrac{1}{3} - \dfrac{2}{15} = \dfrac{1}{5}

3 0
3 years ago
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