Lets make k equal to Kate's age and j equal to Joey's age. If in 5 years Kate will be twice as old as Joe, you can write the equation k+5=2(j+5) and then simplify it to make it easier to work with.
k+5=2(j+5)
k+5=2j+10
k+5-2j=10
k-2j=5
since we know that right know Kate is 11 years older than Joey, you can write the equation k+j=11. Since you know have two equations with with the same variable, you can make a system of equations as fallows:
k-2j=5
k+j=11
Since you need to figure out how old Joey is, you need to somehow get k to cancel out. The easiest thing to do for this problem is to is multiply the top equation by -1 to get:
-k+2j=-5 (you have to add the bottom equation to the top equation)
k+j=11 (-k+k=0, 2j+j=3j, and -5+11=6)
Since k got canceled out, you are left with the equation 3j=6 which means j=2.
Therefore, Joey's current age is 2.
I hope this helps.
factor 20 out of 20cx*3 =540y*3
so you get 20(cx*3=540y*3) if that is what you are looking for
Answer:
Step-by-step explanation:
hello : Completing The Square
X²+y²-10x-16y+53=0 means : (x²-10x+25-25)+(y²-16y+16-16)+53 =0
(x²-10x+25)-25)+(y²-16y+64)-64+53 =0
(x+5)²+(y-8)² -25-64+53=0
(x+5)²+(y-4)² = 6² standard form
the center is (-5 , 4) and the radius : 6
Answer:
Step-by-step explanation:
y - 4 = -(x - 2)
y - 4 =-x + 2
y = -x + 6
The probability of the union of two events is the sum of their probability, minus the probability of their interserction:

If we plug the known values into this formula, we have

From which we can deduce

So, the probability of
is a bit less than
, we have to take away all events that belong to B as well:
