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juin [17]
3 years ago
13

Round to the nearest tenth 20.3

Mathematics
2 answers:
creativ13 [48]3 years ago
8 0
The answer is 20 because 3 is closer t 1 than 10
laila [671]3 years ago
8 0
The answer is 20 because .3 is in the tenth a place and rounds down to 0.
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goblinko [34]
Formula
V = (1/3) pi * r^2 h

pi = 3.14
d = 3 cm. (very small)
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h = 7 cm

V= (1/3) 3.14 * 1.5^2 * 7
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V = 16.485 cm^3

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3 0
3 years ago
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T = 4v + 3<br> (a)<br><br> (b) Make V the subject of the formula T = 4v + 3
Natasha2012 [34]
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3 years ago
A company compiles data on a variety of issues in education. In 2004 the company reported that the national college​ freshman-to
nasty-shy [4]

Answer:

1) Randomization: We assume that we have a random sample of students

2) 10% condition, for this case we assume that the sample size is lower than 10% of the real population size

3) np = 500*0.66= 330 >10

n(1-p) = 500*(1-0.66) =170>10

So then we can use the normal approximation for the distribution of p, since the conditions are satisfied

The population proportion have the following distribution :

p \sim N(p,\sqrt{\frac{\hat p(1-\hat p)}{n}})  

And we have :

\mu_p = 0.66

\sigma_{p}= \sqrt{\frac{0.66(1-0.66)}{500}}= 0.0212

Using the 68-95-99.7% rule we expect 68% of the values between 0.639 (63.9%) and 0.681 (68.1%), 95% of the values between 0.618(61.8%) and 0.702(70.2%) and 99.7% of the values between 0.596(59.6%) and 0.724(72.4%).

Step-by-step explanation:

For this case we know that we have a sample of n = 500 students and we have a percentage of expected return for their sophomore years given 66% and on fraction would be 0.66 and we are interested on the distribution for the population proportion p.

We want to know if we can apply the normal approximation, so we need to check 3 conditions:

1) Randomization: We assume that we have a random sample of students

2) 10% condition, for this case we assume that the sample size is lower than 10% of the real population size

3) np = 500*0.66= 330 >10

n(1-p) = 500*(1-0.66) =170>10

So then we can use the normal approximation for the distribution of p, since the conditions are satisfied

The population proportion have the following distribution :

p \sim N(p,\sqrt{\frac{\hat p(1-\hat p)}{n}})  

And we have :

\mu_p = 0.66

\sigma_{p}= \sqrt{\frac{0.66(1-0.66)}{500}}= 0.0212

And we can use the empirical rule to describe the distribution of percentages.

The empirical rule, also known as three-sigma rule or 68-95-99.7 rule, "is a statistical rule which states that for a normal distribution, almost all data falls within three standard deviations (denoted by σ) of the mean (denoted by µ)".

On this case in order to check if the random variable X follows a normal distribution we can use the empirical rule that states the following:

• The probability of obtain values within one deviation from the mean is 0.68

• The probability of obtain values within two deviation's from the mean is 0.95

• The probability of obtain values within three deviation's from the mean is 0.997

Using the 68-95-99.7% rule we expect 68% of the values between 0.639 (63.9%) and 0.681 (68.1%), 95% of the values between 0.618(61.8%) and 0.702(70.2%) and 99.7% of the values between 0.596(59.6%) and 0.724(72.4%).

8 0
3 years ago
A political candidate has asked you to conduct a poll to determine what percentage of people support her. If the candidate only
Neporo4naja [7]
Idk maybe it's is 10x32/20=60
5 0
3 years ago
The Harris family needs to purchase topsoil for their landscaping project (measuring 50 ft x 40 ft with a thickness of 6 inches
lana66690 [7]
50ft x 40ft x 0.5ft = 1,000 ft³ of soil needed for the project

1000/3= 333.3 bags of soil would be needed, so round up to 334.
334 x $2.25 = $751.50

convert the feet³ to yards³, divide the 1000 ft³ by 27 (27 ft³ in 1 yard³)
1000/27= 37.037(repeating) yd³ I'll round up to 38 yd³
38yd³ x $18 = $684 + $50 delivery fee = $734

So, the bulk soil is less expensive by $17.50
7 0
3 years ago
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