3 years ago

If f(1)=1 and f(n)=(n-2)^2 +n then find the value of f(3)

Mathematics

1 answer:

Blababa [14]3 years ago

4 0

Answer:

f(3) =4

Step-by-step explanation:

f(n)=(n-2)^2 +n

We want to find f(3)

Put in n=3

f(3) = (3-2) ^2 +3

f(3) = 1^2 +3

f(3) =1+3

f(3) =4

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