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balu736 [363]
3 years ago
5

Jada has 7/8 cup of cheese. Her cheese bread recipe calls for 1/6 cup of cheese . How many times can she make her recipe with th

e cheese she has?
Mathematics
2 answers:
Tems11 [23]3 years ago
7 0

Answer:

5 times

Step-by-step explanation:

Quantity of cheese available = 7/8

Quantity needed to make a bread recipe = 1/6

Number of bread recipes that can be made

= 7/8 ÷1/6

= 7/8 × 6/1

= 5.25

From above, she can make 5 bread recipes from the 7/8 cup of cheese she has.

masha68 [24]3 years ago
4 0
You need to have the common denominator and once you do see how many times the 1/6cup will go into the 7/8cup which is 5
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Find the arc length of the given curve between the specified points. x = y^4/16 + 1/2y^2 from (9/16), 1) to (9/8, 2).
lutik1710 [3]

Answer:

The arc length is \dfrac{21}{16}

Step-by-step explanation:

Given that,

The given curve between the specified points is

x=\dfrac{y^4}{16}+\dfrac{1}{2y^2}

The points from (\dfrac{9}{16},1) to (\dfrac{9}{8},2)

We need to calculate the value of \dfrac{dx}{dy}

Using given equation

x=\dfrac{y^4}{16}+\dfrac{1}{2y^2}

On differentiating w.r.to y

\dfrac{dx}{dy}=\dfrac{d}{dy}(\dfrac{y^2}{16}+\dfrac{1}{2y^2})

\dfrac{dx}{dy}=\dfrac{1}{16}\dfrac{d}{dy}(y^4)+\dfrac{1}{2}\dfrac{d}{dy}(y^{-2})

\dfrac{dx}{dy}=\dfrac{1}{16}(4y^{3})+\dfrac{1}{2}(-2y^{-3})

\dfrac{dx}{dy}=\dfrac{y^3}{4}-y^{-3}

We need to calculate the arc length

Using formula of arc length

L=\int_{a}^{b}{\sqrt{1+(\dfrac{dx}{dy})^2}dy}

Put the value into the formula

L=\int_{1}^{2}{\sqrt{1+(\dfrac{y^3}{4}-y^{-3})^2}dy}

L=\int_{1}^{2}{\sqrt{1+(\dfrac{y^3}{4})^2+(y^{-3})^2-2\times\dfrac{y^3}{4}\times y^{-3}}dy}

L=\int_{1}^{2}{\sqrt{1+(\dfrac{y^3}{4})^2+(y^{-3})^2-\dfrac{1}{2}}dy}

L=\int_{1}^{2}{\sqrt{(\dfrac{y^3}{4})^2+(y^{-3})^2+\dfrac{1}{2}}dy}

L=\int_{1}^{2}{\sqrt{(\dfrac{y^3}{4}+y^{-3})^2}dy}

L= \int_{1}^{2}{(\dfrac{y^3}{4}+y^{-3})dy}

L=(\dfrac{y^{3+1}}{4\times4}+\dfrac{y^{-3+1}}{-3+1})_{1}^{2}

L=(\dfrac{y^4}{16}+\dfrac{y^{-2}}{-2})_{1}^{2}

Put the limits

L=(\dfrac{2^4}{16}+\dfrac{2^{-2}}{-2}-\dfrac{1^4}{16}-\dfrac{(1)^{-2}}{-2})

L=\dfrac{21}{16}

Hence, The arc length is \dfrac{21}{16}

6 0
2 years ago
F(x) = x^2 - 4, X is greater/less than 0<br><br> (a) Find the inverse function of f.<br> F^-1(x) =
Natali5045456 [20]

Step-by-step explanation:

f(x) = x² - 4

y = x²-4

x = y²-4

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y =  \sqrt{x + 4}

7 0
2 years ago
18.
ludmilkaskok [199]

Answer:

C. y = -4/5x - 2

Step-by-step explanation:

Graph the line using the slope and y-intercept, or two points.

Slope:  

−

4

5

y-intercept:  

(

0

,

−

2

)

x

y

−

5

2

0

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4 0
3 years ago
Suppose that you earned a​ bachelor's degree and now​ you're teaching high school. The school district offers teachers the oppor
stepan [7]

Answer:

Step-by-step explanation:

Answer:

a. The amount that is saved at the expiration of the 5 year period is $22,769.20¢

b. The amount of interest is $2,769.20¢

Step-by-step explanation:

Since the amount that is deposited every year for a period of five years is $4,000 and the rate of the interest is 6.5%. We can always calculate the amount that is saved at the expiration of the five years.

    We will first state the formula for calculating the future value of annuity:-

      Future value of annuity =

                      P[\frac{(1 + r)^{t}-1 }{r}]

   Where P is the amount deposited per year.

   r is the rate of interest

   t is the time or period

 

    and in this case, the actual value of P = $4,000

      rate of interest, r is 6.5% = 0.065

      time, t is 5 years.

   Substituting e, we have:

   Fv of annuity =

                          4,000[\frac{(1 + 0.065)^{5}-1 }{0.065 }]

   = 4,000 × [((1.065)^5)- 1/0.065]

 = 4,000 × [(1.37 - 1)/0.065]

 = 4,000 × (0.37/0.065)

 = 4,000 × 5.6923

 = $22,769.20¢

a. Therefore the amount that is saved at the end of the five (5) years is $22,769.20¢

b. To find the interest, we will calculate the amount of deposit made during the period of five years and subtract the sum from the current amount that is saved ($22,769.29¢).

  Since I deposited 4,000 every year for five years, the total amount of deposit I made at the period =

       4,000 × 5 = $20,000

  The amount of interest is then = $22,769.20¢ - $20,000 = $2,769.20¢

3 0
3 years ago
ILL MARK U BRAINLIEST
Vladimir79 [104]

Answer:

-6x-16

Step-by-step explanation:

5 0
3 years ago
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