Step-by-step explanation:
arctan(x) is less than π/2 for x > 0. Therefore, if we say g(x) = 13 (π/2) / eˣ, then f(x) < g(x) for all values of x > 0.
g(x) = 13 (π/2) / eˣ
g(x) = 13π/2 · (1/e)ˣ
So g(x) is a geometric series where r = 1/e. Since |r| < 1, the series converges.
Since g(x) converges, the smaller f(x) also converges.
Let n and d represent the numerator and denominator of the fraction.
.. (n +1)/(d +1) = 4/5
.. (n -5)/(d -5) = 1/2
Eliminating fractions from these equations gives
.. 5(n +1) = 4(d +1)
.. 2(n -5) = (d -5)
Subtracting the first equation from 4 times the second gives
.. 4(2(n -5)) -(5(n +1)) = 4(d -5) -(4(d +1))
.. 8n -40 -5n -5 = 4d -20 -4d -4
.. 3n = 21
.. n = 7
.. 2(7 -5) = d -5
.. 9 = d
The fraction is 7/9.
A train leaves the station at time xequals
0.
Traveling at a constant speed, the train travels 328
km in 3.4
h. Round to the nearest 10 km and the nearest whole hour. Then represent the distance, y, the train travels in x hours using a table, an equation, and a graph. give brainliest x
The value of the expression given as [3² * 3⁻⁵]/[5⁻²] is 25/27
<h3>How to evaluate the expression?</h3>
The expression is given as:
3 squared times 3 to the power of negative 5 end quantity over 5 to the power of negative two
Rewrite properly as:
[3² * 3⁻⁵]/[5⁻²]
Apply the negative exponent law of indices
So, we have
[3² * 3⁻⁵]/[5⁻²] = [5²]/[3⁻² * 3⁵]
Apply the exponent law of indices
[3² * 3⁻⁵]/[5⁻²] = [5²]/[3³]
This gives
[3² * 3⁻⁵]/[5⁻²] = 25/27
Hence, the value of the expression given as [3² * 3⁻⁵]/[5⁻²] is 25/27
Read more about expressions at:
brainly.com/question/723406
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Step-by-step explanation:
Find the slope of JK by the formula :y2-y1/(x2-x1) whose value is 4/5
similarly, calculate the slope of GH it's value is also 4/5
Find slope of GK now by same formula y2-y1/( x2-x1 ).the value will be -5/3
Similarly calculate slope of HJ and you will get its value to be -5/3
since parallel lines have equal slopes JK and GH are parallel and GK and HJ are parallel. Since opposite sides are parallel GHJk is parallelogram