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tresset_1 [31]
3 years ago
11

Need help with this, i dont understand so please also explain!

Mathematics
1 answer:
Ne4ueva [31]3 years ago
3 0
The rule for dividing exponents is:
For exponents with the same base, you can subtract the exponents and put the difference as exponent over the base. Remember that the fraction bar acts as a division sign! Or: \frac{ a^{m} }{a^{n} } = a^{m} \div a^{n} = a^{m-n}

For example: \frac{ a^{5} }{a^{2} } = a^{5} \div a^{2} = a^{5-2} =  a^{3}

Back to your problem:
You're asked to simplify \frac{a^{12}  b^{8} }{a^{2}  b^{4}}.

Use your exponent rule for dividing exponents. 
\frac{a^{12} b^{8} }{a^{2} b^{4}}\\ 
= a^{(12-2)} b^{(8-4)}\\
= a^{10}  b^{4}
---
Answer: a^{10} b^{4}

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44 prime factorization
il63 [147K]

Answer:

2 * 2 * 11

Step-by-step explanation:

Find the set of prime numbers that, when multiplied together, give 44.

:)

6 0
3 years ago
PLEASE HELPPPPPPP
uysha [10]

Answer:

the answer would be 1,-8

6 0
2 years ago
Do you know the answer toPart A: 25% of 50 = Part B: 25% of 60 = Part C: 50% of 60 = Part D: 75% of 60 = Part E: 75% of 30 = Par
Verdich [7]

Answer:

Part A: 25% of 50 = 12.5

Part B: 25% of 60 = 15

Part C: 50% of 60 = 30

Part D: 75% of 60 = 45

Part E: 75% of 30 = 22.5

Part F: 100% of 22.5 = 22.5

Part G: 10% of 22.5 = 2.25

Part H: 50% of 45.7 = 22.85

Step-by-step explanation:

To find - Do you know the answer to

              Part A: 25% of 50 =

              Part B: 25% of 60 =

              Part C: 50% of 60 =

              Part D: 75% of 60 =

              Part E: 75% of 30 =

              Part F: 100% of 22.5 =

              Part G: 10% of 22.5 =

              Part H: 50% of 45.7 =

Proof -

Part A :

25% of 50 =  \frac{25}{100} *50 = \frac{1}{4}*50 = 12.5

⇒25% of 50 = 12.5

Part B :

25% of 60 =  \frac{25}{100} *60 = \frac{1}{4}*60 = 15

⇒25% of 60 = 15

Part C :

50% of 60 =  \frac{50}{100} *60 = \frac{1}{2}*60 = 30

⇒50% of 60 = 30

Part D :

75% of 60 = \frac{75}{100} *60 = \frac{75}{10}*6 = 45

⇒75% of 60 = 45

Part E :

75% of 30 = \frac{75}{100} *30 = \frac{75}{10}*3 = 22.5

⇒75% of 30 = 22.5

Part F :

100% of 22.5 = \frac{100}{100} *22.5 = 22.5

⇒ 100% of 22.5 = 22.5

Part G :

10% of 22.5 = \frac{10}{100} *22.5 = 2.25

⇒ 10% of 22.5 = 2.25

Part H :

50% of 45.7 =  \frac{50}{100} *45.7 = \frac{1}{2}*45.7 = 22.85

⇒50% of 45.7 = 22.85

6 0
3 years ago
A metalworker has a metal alloy that is 15% copper and another alloy that is 75% copper. How many kilograms of each alloy should
attashe74 [19]
X - the mass of the first alloy (15%)
y - the mass of the second alloy (75%)

x kg of the first alloy contains 15%x=0.15x=(15/100)x=(3/20)x kg of copper
y kg of the second alloy contains 75%y=0.75y=(75/100)y=(3/4)y kg of copper
90 kg of a 51% copper alloy contains 51%*90=0.51*90=45.9 kg of copper

x+y=90 \\
\frac{3}{20}x+\frac{3}{4}y=45.9 \ \ \ |\times (-\frac{4}{3}) \\ \\
x+y=90 \\
\underline{-\frac{1}{5}x-y=-61.2} \\
x-\frac{1}{5}x=90-61.2 \\
\frac{4}{5}x=28.8 \ \ \ |\times \frac{5}{4} \\
x=36 \\ \\
36+y=90 \\
y=90-36 \\
y=54

The metal worker should combine 36 kg of the 15% copper alloy and 54 kg of the 75% copper alloy to create 90 kilograms of a 51% copper alloy.
7 0
3 years ago
S is the set of prime numbers that are less than 15.. A) 2,3,5,7,11,13. B)2,3,5,7,9,11,13. C)1,3,5,7,9,11,13. D)1,2,3,4,5,6,7,8,
hichkok12 [17]
It is       aaaaaaaaaaaaaaaaa

8 0
3 years ago
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