Question

Mr. Lance keeps a jar of candy on his desk for students to pick from when they do well on a test. The jar contains 5 Snickers, 2 Butterfingers, 4 Almond Joys and 3 Milky Ways. If two students get to pick candy from the jar, what is the probability that the first student picks a Snickers and then the second student also picks a Snickers?

Answer 1

Answer: $\dfrac{10}{91}$

Step-by-step explanation:

Given : The jar contains 5 Snickers, 2 Butterfingers, 4 Almond Joys and 3 Milky Ways.

Total candies in the jar =$5+2+4+3=14$

Provability that firsts student select snickers =$\dfrac{5}{14}$

Now total candies in jar = 14-1=13

Total snickers remained =5-1=4

Probability that the second student also select snickers=$\dfrac{4}{13}$

Then, the probability that the first student picks a Snickers and then the second student also picks a Snickers :-

$\dfrac{5}{14}\times\dfrac{4}{13}=\dfrac{20}{182}=\dfrac{10}{91}$

Hence, the required probability = $\dfrac{10}{91}$

Answer 2

3/14 for the first kid and 2/13 for the 2nd kid