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pav-90 [236]
3 years ago
13

Alex leaves school to go home. He walks 11 meters North and then 10 meters West. How far is Alex from the school?

Mathematics
1 answer:
yuradex [85]3 years ago
3 0

Answer:

~15 meters away

Step-by-step explanation:

c^2 = a^2+b^2

c^2 = 10^2+11^2

c^2 = 100+121

c^2 = 221

c = \sqrt{221}

c = ~15

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Jasmine’s age is 4 times her age 10 years ago. Write an equation that represents the statement.
aleksandr82 [10.1K]

Answer:

x + 10 = 4x

Step-by-step explanation:

Let x = her age 10 years ago.

Her age now is x + 10.

x + 10 = 4x

5 0
1 year ago
7x + 4y = 2<br> 7x + 2y = 8
Mariana [72]

Answer:

x  =  2 , y  =  − 3

Step-by-step explanation

Solve for the first variable in one of the equations, then substitute the result into the other equation.

Point Form: ( 2 , − 3 )

Equation Form: x  =  2 , y  =  − 3

3 0
3 years ago
3x+10=4x+10 what is the answer?
ValentinkaMS [17]

Answer:

x is 0.

Step-by-step explanation:

 Subtract both sides by 3x. Then, you will have 10= x+10. Subtract 10 on both sides to isolate x, then you will have x=0. Therefore, this equation on both sides has a solution of 0. Hope this helps!

4 0
3 years ago
Read 2 more answers
Parking at a university has become a problem. University administrators are interested in determining the average time it takes
Vikentia [17]

Answer:

<h2>In this particular case,the target population of interest to the university administration constitutes the university students.</h2>

Step-by-step explanation:

  • The university administration is interested to conduct a statistical study to identify the average or mean time taken by the students to find a vacant parking spot.
  • Therefore,the research topic here is the average time taken by the university students to find parking spot. The administrator collects an inconspicuous sample of 240 samples from the target population of the study,which is the overall student population of the university.
  • The sample collected by the university administration is used to observe the average or mean parking time by the university students.
6 0
3 years ago
Machine A produces bolts at a uniform rate of 120 every 40 seconds, and Machine B produces bolts at a uniform rate of 100 every
Nutka1998 [239]

Answer:

25 seconds

Step-by-step explanation:

Hi there!

In order to answer this question, first we need to know how many bolts per second are produced by each machine, this can be known by dividing the number of bolts by the time it takes.

For machine A:

A = \frac{120 bolts}{40 s}= 3 \frac{bolts}{s}

For machine B:

B = \frac{100 bolts}{20 s}= 5 \frac{bolts}{s}

So, if the two machines run simultaneously, we will have a rate of prodcution of bolts equal to the sum of both:

A+B=(3+5)\frac{bolts}{s}=8\frac{bolts}{s}

Now, we need to know how much time it will take to producee 200 bolts, to find this out we need to divide the amount of bolts by the production rate:

t = \frac{bolts}{ProductionRate}= \frac{200 bolts}{8 \frac{bolts}{s} }

The <em>bolts</em> unit cancell each other and we are left with <em>seconds</em>

t = \frac{200}{8} s = 25 s

So it will take 25 seconds to produce 200 bolts with machine A and B running simultaneously.

Greetings!

4 0
4 years ago
Read 2 more answers
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