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pav-90 [236]
3 years ago
13

Alex leaves school to go home. He walks 11 meters North and then 10 meters West. How far is Alex from the school?

Mathematics
1 answer:
yuradex [85]3 years ago
3 0

Answer:

~15 meters away

Step-by-step explanation:

c^2 = a^2+b^2

c^2 = 10^2+11^2

c^2 = 100+121

c^2 = 221

c = \sqrt{221}

c = ~15

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<h2>Given :-</h2>

Initial speed (v) = 1.9m/s

Final speed (u) = 3.8m/s

Time (t) = 11 s

<h2>Formula Used :-</h2>

v = u + a×t(a = acceleration)

➾ a = {\frac{u-v}{t}}

<h2>Solution:-</h2>

a = {\frac{u-v}{t}} (putting the value of v, u and t from above)

➾ a = {\frac{3.8-1.9}{11}}

➾ a = {\frac{1.9}{11}}

➾ a = 0.17 m/s (approx.)

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