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pav-90 [236]
2 years ago
13

Alex leaves school to go home. He walks 11 meters North and then 10 meters West. How far is Alex from the school?

Mathematics
1 answer:
yuradex [85]2 years ago
3 0

Answer:

~15 meters away

Step-by-step explanation:

c^2 = a^2+b^2

c^2 = 10^2+11^2

c^2 = 100+121

c^2 = 221

c = \sqrt{221}

c = ~15

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Note: Enter your answer and show all the steps that you use to solve this problem in the space provided.
KiRa [710]

Answer:

1863 meters^{2}

Step-by-step explanation:

( 23 x 12 ) x 2 = 552

69 x 19 = 1311

 1311

<u>+552</u>

= 1863 meters^{2}

8 0
2 years ago
Jillian measured the distance around a small fish pond as 27 yards. Which would be a good estimate for the distance across the p
ankoles [38]
27 (circumference) ➗ 3.14 (pi) = 8.59 (diameter)

Distance across (diameter) would be closest to 9.
4 0
3 years ago
If you have a vertical angle and the side angles are 83 and 83 whats the other one?
Hoochie [10]

Answer:

97°

Step-by-step explanation:

you do 83*2=166 and then 360-166=194 which is the total sum of the two unknown vertical angles. once you have that, divide it by 2 to get 194/2=97° as the measure of each individual unknow vertical angle

7 0
3 years ago
Read 2 more answers
If sinA =3/5 and A+B =90 find cosB
-Dominant- [34]

A+B=90^o\to B=90^o-A\\\\\cos B=\cos(90^o-A)=\cos90^o\cos A+\sin90^o\sin A\\\\=\cos A+1\cdot\dfrac{3}{5}=0+\dfrac{3}{5}=\dfrac{3}{5}\\\\\boxed{\cos B=\dfrac{3}{5}}

Used:\\\\\cos(x+y)=\cos x\cos y+\sin x\sin y\\\\\cos90^o=0,\ sin90^o=1

Other method:

Look at the picture.

\sin\theta=\dfrac{opposite}{hypotenuse}\\\\\sin A=\dfrac{3}{5}\to opposite=3\ and\ hypotenuse=5

\cos\theta=\dfrac{adjacent}{hypotenuse}\\\\adjacent=3\ and\ hypotenuse=5\to\cos B=\dfrac{3}{5}

8 0
3 years ago
Which number has the greatest value? <br><br>a) 0.38<br>b) 08.2<br>c) 02.8<br>d) 2.80
Elis [28]

Answer:

the correct answer would be b)8.2

Step-by-step explanation:


6 0
3 years ago
Read 2 more answers
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