Answer:
Rough endoplasmic reticulum looks "rough" under a microscope because it has ribosomes attached to its surface.
Explanation:
Rough endoplasmic reticulum (RER) is a membrane organelle found in the cytoplasm of eukaryotic cells, which has ribosomes attached to its outer surface. Hence the name, rough endoplasmic reticulum. It has an important role in the synthesis of proteins. In ribosomes, the proteins are synthesized. The smooth endoplasmic reticulum (SER) does not contain ribosomes. It has an impotant role in the synthesis and storage of lipids. The proteins that are synthesized in the ribosomes are packaged into vesicles and transported to the Golgi apparatus by the rough endoplasmic reticulum. The Golgi apparatus which is located near the RER, modifies, transports and packages proteins for delivery to targeted destinations.
Chemical reactions occur when chemical bonds between atoms are formed or broken. If this is what you mean because the question is really confusing sorry :(
Answer:<span>The hyphae structures in the organism . .</span>
Answer:
Fructose 2,6‑bisphosphate (F26BP) activates phosphofructokinase‑1 (PFK -1) and inhibits fructose 1,6‑bisphosphatase (FBPase)
Explanation:
Fructose 2,6‑bisphosphate (F26BP) is a metabolite that is produced with an increase in glucose, hence increasing the availability of fructose-6-phosphate. With, the increased concentration of F26BP, it increases the affinity of PFK- 1 to fructose-6-phosphate, thereby activating glycolysis which enhances the catabolism of glucose. In contrast, F26BP inhibits the activity of fructose 1,6‑bisphosphatase (FBPase), hence inhibiting gluconeogenesis. Gluconeogenesis (formation of glucose) will not be need since there is the presence of glucose in the system.
In summary, fructose 2,6‑bisphosphate (F26BP) reciprocally controls the enzymatic activity of phosphofructokinase‑1 (PFK -1) and fructose 1,6‑bisphosphatase (FBPase); it inhibits gluconeogenesis by inhibiting the enzyme, FBPase and activates glycolysis by activating the enzyme PFk -1