Question

Assuming H-W equilibrium, find both the allele and genotype frequencies. a. In Drosophilia, the allele for normal length wings is dominant over the allele for vestigial wings. In a population of 1,000 individuals, 160 show the recessive phenotype.

Answer 1

Hardy Weinberg Equilibrium

Explanation:

• The frequency of the prevailing (typical) allele in the populace (p) is basically 1 - 0.02 = 0.98 (or 98%). The level of heterozygous people (bearers) in the populace.
• 2pq equivalents the recurrence of heterozygotes or transporters, at that point the condition will be as per the following: 2pq = (2)  .
• The every individual's genotype, check the quantity of duplicates of every allele, and separation by the total number of gene copies.
• Sickle cell attribute was identified in 20.2% of populace though 1.2% was influenced with sickle cell iron deficiency. The allele recurrence of HbA and HbS alleles were 0.89 and 0.11.
• p2 speaks to the recurrence of the homozygous genotype AA, q2 speaks to the recurrence of the homozygous genotype aa, and 2pq speaks to the recurrence of the heterozygous genotype Aa.
• The entirety of the allele frequencies for all the alleles at the locus must be 1, so p + q = 1.