Question

find the solution to the equation by completing the square x^2-6x=7. what is the smallest and largest value of x

Answer 1

Answer:

smallest value of x = -1

Largest value of x = 7

Step-by-step explanation:

$x^2-6x=7$

coefficient of x = -6

Half of the coefficient of x = -6/2 = -3

Square of the half value $=(-3)^2=9$

Add the square value on both sides of equation

$x^2-6x+9=7+9$

$(x-3)^2=16$

Take square root

$x-3= \pm \sqrt{16}$

$x-3= \pm 4$

$x-3=+4$ or $x-3=-4$

$x=+4+3$ or $x=-4+3$

$x=7$ or $x=-1$

Hence smallest value of x = -1

Largest value of x = 7