Answer:
- How does their confidence level compare to the confidence level of the interval stated above?
Provided all the other parameters involved in the determination of margin of error remains constant, the confidence level of the interval obtained by the second set of researchers (with a larger margin of error) is definitely greater than the confidence of the first stated interval.
- How will the margin of error of the 95% confidence interval constructed based on data from the new survey compare to the margin of error of the interval stated above?
Provided all the other parameters involved in the determination of margin of error remains constant, the margin of error of the confidence interval of data from the new survey will be less than the margin of error of the initially stated interval because the margin of error is inversely proportional to the sample size and the sample size of the new survey (2500) is more than the sample size of the old survey (1155).
Step-by-step explanation:
Confidence Interval for the population mean is basically an interval of range of values where the true population mean can be found with a certain level of confidence.
Mathematically,
Confidence Interval = (Sample mean) ± (Margin of error)
Margin of Error is the width of the confidence interval about the mean.
It is given mathematically as,
Margin of Error = (Critical value) × (standard Error of the mean)
Since the sample sizes are so large, the critical value for this would be obtained from the z-distribution tables.
And critical value increases with higher confidence level.
Which directly translates to margin of error increasing with higher confidence level.
A) Hence, if all other parameters stay the same, the margin of error can only be larger if the confidence level of the second researchers is more than than the confidence level at which the initial research was carried out.
B) In the determination of the margin of error
Margin of Error = (Critical value) × (standard Error of the mean)
Standard error of the mean = σₓ = (σ/√n)
where σ = population standard deviation or sample standard deviation for a sample size that's very large
n = sample size
If the critical value stays the same (the tests in the two years being considered are performed at the same level) and the standard deviation too remain almost the same (the question asks us to assume that the population characteristics, with respect to how much time people spend relaxing after work, have not changed much within a year), the margin of error is obviously inversely proportional to the sample size.
Margin of error = (zσ/√n)
zσ = constant = k
Margin of error = (k/√n)
So, if the sample size increases, the new margin of error that will be obtained will be lesser.
Hope this Helps!!!
