Answer:
0.04
I rounded to one significant figures.
Answer: The required probability of selecting 1 red apple and 2 yellow apples is 36.36%.
Step-by-step explanation: We are given that a bag contains 6 red apples and 5 yellow apples out of which 3 apples are selected at random.
We are to find the probability of selecting 1 red apple and 2 yellow apples.
Let S denote the sample space for selecting 3 apples from the bag and let A denote the event of selecting 1 red apple and 2 yellow apples.
Then, we have

Therefore, the probability of event A is given by

Thus, the required probability of selecting 1 red apple and 2 yellow apples is 36.36%.
The third integer is 86, hope this helps :)
Answer negative 9 is the answer
Step-by-step explanation:
Answer:
5x+10y+5z
Step-by-step explanation:
Distributive Property means you multiply each component by the value you are distributing in this case: (1/2)(10x) + (1/2)(20y) + (1/2)(10z) which will yield 5x+10y+5z