Answer:
Cot(theta) = - 0.75 or -3/4
Step-by-step explanation:
The hypotenuse is 5
The y value is 4
We need to find the corresponding x value.
x^2 + y^2 = z^2
X = ?
y = 4
z = 5
x^2 + 4^2 = 5^2
x^2 + 16 = 25
x^2 = 9
Now in this case, you are in quadrant 2, so the x value is - 3
sqrt(x^2) = sqrt(9)
x = - 3
The cot value is the adjacent (x value) / the opposite ( y ) value
Cot(theta) = -3/4
cot(theta) = -0.75
Answer:
50
Step-by-step explanation:
1÷6×150=25
1÷6×150=25
ans:25+25
=50
Answer:
A) y + 1 = -3 ( x - 7 )
Step-by-step explanation:
I used the Desmos website. Hope this helps.
45+5.25n>108
-45 -45
————————
5.25n > 63
Divide both sides by 5.25
n>12
if the diameter is 20, the its radius must be half that or 10.
![\textit{area of a sector of a circle}\\\\ A=\cfrac{\theta \pi r^2}{360}~~ \begin{cases} r=radius\\ \theta =\stackrel{degrees}{angle}\\[-0.5em] \hrulefill\\ A=5\pi \\ r=10 \end{cases}\implies \begin{array}{llll} 5\pi =\cfrac{\theta \pi (10)^2}{360}\implies 5\pi =\cfrac{5\pi \theta }{18} \\\\\\ \cfrac{5\pi }{5\pi }=\cfrac{\theta }{18}\implies 1=\cfrac{\theta }{18}\implies 18=\theta \end{array}](https://tex.z-dn.net/?f=%5Ctextit%7Barea%20of%20a%20sector%20of%20a%20circle%7D%5C%5C%5C%5C%20A%3D%5Ccfrac%7B%5Ctheta%20%5Cpi%20r%5E2%7D%7B360%7D~~%20%5Cbegin%7Bcases%7D%20r%3Dradius%5C%5C%20%5Ctheta%20%3D%5Cstackrel%7Bdegrees%7D%7Bangle%7D%5C%5C%5B-0.5em%5D%20%5Chrulefill%5C%5C%20A%3D5%5Cpi%20%5C%5C%20r%3D10%20%5Cend%7Bcases%7D%5Cimplies%20%5Cbegin%7Barray%7D%7Bllll%7D%205%5Cpi%20%3D%5Ccfrac%7B%5Ctheta%20%5Cpi%20%2810%29%5E2%7D%7B360%7D%5Cimplies%205%5Cpi%20%3D%5Ccfrac%7B5%5Cpi%20%5Ctheta%20%7D%7B18%7D%20%5C%5C%5C%5C%5C%5C%20%5Ccfrac%7B5%5Cpi%20%7D%7B5%5Cpi%20%7D%3D%5Ccfrac%7B%5Ctheta%20%7D%7B18%7D%5Cimplies%201%3D%5Ccfrac%7B%5Ctheta%20%7D%7B18%7D%5Cimplies%2018%3D%5Ctheta%20%5Cend%7Barray%7D)
