Question

Find the equation of the axis of symmetry and the coordinates of vertex of the functions =2x^2+4x-3

Answer 1

Hello,

Find the equation of the axis of symmetry is like find the maximum or minimum point of this function.

$f(x)=2x^2+4x-3\\\\\alpha=-\dfrac{b}{2a}=-\dfrac{4}{4}=-1$

The equation of the axis of symmetry is then :   $x=-1$

$\beta=f(\alpha)=2(-1)^2+4(-1)-3=2-4-3=-5$

Coordinates of vertex :   $(\alpha,\beta)=(-1;-5)$