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kherson [118]
3 years ago
11

URGENT!!!

Mathematics
1 answer:
garri49 [273]3 years ago
3 0

Answer:

B:  (x - 4)² = 44

Step-by-step explanation:

Start with x^2 - 8x - 10  =  18.

Simplify the constants by adding 10 to both sides:  x^2 - 8x - 10 + 10 = 18 + 10.

Then x^2 - 8x = 28.

Now identify the coefficient of x.  It is -8.  

Take half of this, obtaining -4.

Square this result, obtaining 16.

Add 16, and then subtract 16, to x^2 - 8x:

x^2 - 8x + 16 - 16 = 28.

Add 16 to both sides:

x^2 - 8x + 16 = 28 + 16 = 44

Rewrite x^2 - 8x + 16 as (x - 4)², so that we have:

(x - 4)² = 44.  This is in the form (x - p)² = 44, and matches Answer B.

Note:  Please use " ^ " to indicate exponentiation:  (x - 4)^2 = 44

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</span>


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You flip a coin that is not fair, the prbability of heads on each flip is 0.7. if the coin shows heads, you draw a marble from u
Shkiper50 [21]

Solution :

P(H) = 0.7  ;  P(T) = 0.3

If heads, then Urn H,  1 blue and 4 red marbles.

If tails, then Urn T ,  3 blue and 1 red marbles.

a).

P ( choosing a Red marble )

= P (H) x P( Red from Urn H) + P (T) x P( Red from Urn T)

$=0.7 \times  \frac{4}{5} + 0.3 \times \frac{1}{4}$

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= 0.635

b).  If P (B, if coin showed heads)

If heads, then marble is picked from Urn H.

Therefore,

P (Blue) $=\frac{1}{5}$

             = 0.2

c). P (Tails, if marble was red)

$=P (T/R) = \frac{P(R/T)}{P(R)}  \ P(T)$

Where P (R/T) = P ( red, if coin showed tails)

                        $=\frac{1}{4}$

                        = 0.25 (As Urn T is chosen)

P (R) =  P (Red) = 0.635 (from part (a) )

P (T) = P (Tails) = 0.3

∴ $P(T/R) = \frac{0.25 \times 0.3}{0.635}$

                = 0.118

                 

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