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3 years ago

What are multiples of nine

Mathematics

1 answer:

Dovator [93]3 years ago

5 0

<h2>The multiples of nine are 9, 18, 27, 36, 45, 54, 63, .....</h2>

Step-by-step explanation:

We have,

Nine

To find, the multiples of nine = ?

The multiples of nine are:

1 × 9, 2 × 9, 3 × 9, 4 × 9, 5 × 9, 6 × 9, 7 × 9, .......

= 9, 18, 27, 36, 45, 54, 63, .....

∴ The multiples of nine are 9, 18, 27, 36, 45, 54, 63, .....

Thus, the multiples of nine are 9, 18, 27, 36, 45, 54, 63, ..... .

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Pleas help me find the answer and show the work to this question

lions [1.4K]

Answer:

$Leg\ 1 = 8$

$Leg\ 2 = 15$

Step-by-step explanation:

Given: See Attachment

Required

Determine the length of the legs

To do this, we apply Pythagoras theorem.

$Hyp^2 = Adj^2 + Opp^2$

In this case:

$17^2 = x^2 + (2x- 1)^2$

Open Bracket

$17^2 = x^2 + 4x^2- 2x-2x + 1$

$17^2 = 5x^2 - 4x + 1$

$289= 5x^2 - 4x + 1$

Collect Like Terms

$5x^2 - 4x + 1 - 289 = 0$

$5x^2 - 4x - 288 = 0$

Solving using quadratic formula:

$x = \frac{-b\±\sqrt{b^2 - 4ac}}{2a}$

So:

$x = 8$ or $x = -7.2$

Since, x can't be negative, then:

$x = 8$

One of the leg is:

$Leg\ 1 = x$

$Leg\ 1 = 8$

$Leg\ 2 = 2x - 1$

$Leg\ 2 = 2*8 - 1$

$Leg\ 2 = 16 - 1$

$Leg\ 2 = 15$

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