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3 years ago

Please help click on the image below

Mathematics

1 answer:

damaskus [11]3 years ago

3 0

Yeah the answer would be B. 80 minutes

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A jungle has 578 monkeys.

sergejj [24]

Answer:

425 monkeys

Step-by-step explanation:

Subtract the number of birds from the number of monkeys to find the difference between the two.

7 0

3 years ago

Read 2 more answers

I need help!!! I just need the answer for p and i also need the answer step by step!!

klasskru [66]

Answer:

x = 18

m = 21.2

p = 31.8

Step-by-step explanation:

The ratio of the left-side length to the bottom-side length is the same for both triangles:

x/11.2 = (x +27)/28

28x = 11.2(x +27) = 11.2x +302.4 . . . . . multiply by 11.2·28

16.8x = 302.4 . . . . . . . subtract 11.2x

x = 18 . . . . . . . . . . . . divide by 16.8

The length of m can be found using the Pythagorean theorem. The sum of the squares of the legs is the square of the hypotenuse.

x^2 +11.2^2 = m^2

m = √(324 +125.44) = √449.44 = 21.2

The length of p can also be found using the Pythagorean theorem. We prefer the proportion ...

p/27 = m/x

p = 27(21.2/18) = 31.8

The lengths of the unknown sides in the figure are ...

x = 18

m = 21.2

p = 31.8

8 0

2 years ago

: A sports store sells a total of 70 soccer balls in one month, and collects a total of $2,400. A limited Edition soccer ball is

sweet-ann [11.9K]

Answer:

The store sold 43 pro NSL soccer balls.

The store sold 27 limited Edition soccer balls.

Step-by-step explanation:

Let x represent number of limited Edition soccer balls and y represent the number of pro NSL soccer balls.

We have been given that a sports store sells a total of 70 soccer balls in one month. We can represent this information in an equation as:

$x+y=70...(1)$

Cost of x limited Edition soccer balls: $65x$

Cost of y pro NSL soccer balls: $15x$

We are also told that store collected a total of $2,400. We can represent this information in an equation as:

$65x+15y=2400...(2)$

From equation (1), we will get:

$x=70-y$

Substituting this value in equation (2), we will get:

$65(70-y)+15y=2400$

$4550-65y+15y=2400$

$4550-50y=2400$

$4550-4550-50y=2400-4550$

$-50y=-2150$

$\frac{-50y}{-50}=\frac{-2150}{-50}$

$y=43$

Therefore, the store sold 43 pro NSL soccer balls.

Now, we will substitute $y=43$ in equation (1) to solve for x:

$x+43=70$

$x+43-43=70-43$

[tex]x=27/tex]

Therefore, the store sold 27 limited Edition soccer balls.

4 0

3 years ago

PLEASE HELP !! ILL GIVE BRAINLIEST !!

Nady [450]

Answer:

<QPS and <TSU

4 0

3 years ago

<img src="https://tex.z-dn.net/?f=%5Cleft.%20%5Cbegin%7Bcases%7D%20%7B%208%20x%20%2B%202%20y%20%3D%2046%20%7D%20%5C%5C%20%7B%207

Brut [27]

$\huge \boxed{\mathfrak{Question} \downarrow}$

$\left. \begin{cases} { 8 x + 2 y = 46 } \\ { 7 x + 3 y = 47 } \end{cases} \right.$

$\large \boxed{\mathfrak{Answer \: with \: Explanation} \downarrow}$

$\left. \begin{cases} { 8 x + 2 y = 46 } \\ { 7 x + 3 y = 47 } \end{cases} \right.$

First, write both the equations in its standard form.

$8x+2y=46\\ 7x+3y=47$

Now, write the equations in form of matrix.

$\left(\begin{matrix}8&2\\7&3\end{matrix}\right)\left(\begin{matrix}x\\y\end{matrix}\right)=\left(\begin{matrix}46\\47\end{matrix}\right)$

Then, multiply the equation towards the left by using the inverse of matrix $\left(\begin{matrix}8&2\\7&3\end{matrix}\right)$

$\sf \: inverse(\left(\begin{matrix}8&2\\7&3\end{matrix}\right))\left(\begin{matrix}8&2\\7&3\end{matrix}\right)\left(\begin{matrix}x\\y\end{matrix}\right)=inverse(\left(\begin{matrix}8&2\\7&3\end{matrix}\right))\left(\begin{matrix}46\\47\end{matrix}\right)$

The product of the matrix & its inverse will be the identity matrix.

$\sf\left(\begin{matrix}1&0\\0&1\end{matrix}\right)\left(\begin{matrix}x\\y\end{matrix}\right)=inverse(\left(\begin{matrix}8&2\\7&3\end{matrix}\right))\left(\begin{matrix}46\\47\end{matrix}\right)$

Now, multiply the matrices that lie on the left-hand side of the equal sign.

$\sf\left(\begin{matrix}x\\y\end{matrix}\right)=inverse(\left(\begin{matrix}8&2\\7&3\end{matrix}\right))\left(\begin{matrix}46\\47\end{matrix}\right)$

For the 2 × 2 matrix $\left(\begin{matrix}a&b\\c&d\end{matrix}\right)$ , the inverse matrix is ⇨ $\left(\begin{matrix}\frac{d}{ad-bc}&\frac{-b}{ad-bc}\\\frac{-c}{ad-bc}&\frac{a}{ad-bc}\end{matrix}\right)$ .

$\left(\begin{matrix}x\\y\end{matrix}\right)=\left(\begin{matrix}\frac{3}{8\times 3-2\times 7}&-\frac{2}{8\times 3-2\times 7}\\-\frac{7}{8\times 3-2\times 7}&\frac{8}{8\times 3-2\times 7}\end{matrix}\right)\left(\begin{matrix}46\\47\end{matrix}\right)$

Do the calculations.

$\left(\begin{matrix}x\\y\end{matrix}\right)=\left(\begin{matrix}\frac{3}{10}&-\frac{1}{5}\\-\frac{7}{10}&\frac{4}{5}\end{matrix}\right)\left(\begin{matrix}46\\47\end{matrix}\right)$

Multiply the matrices.

$\left(\begin{matrix}x\\y\end{matrix}\right)=\left(\begin{matrix}\frac{3}{10}\times 46-\frac{1}{5}\times 47\\-\frac{7}{10}\times 46+\frac{4}{5}\times 47\end{matrix}\right)$

Do the arithmetics again.

$\left(\begin{matrix}x\\y\end{matrix}\right)=\left(\begin{matrix}\frac{22}{5} \\\frac{27}{5}\end{matrix}\right)$

Finally, extract the matrix elements x & y & write them separately.

$\large \boxed{ \boxed{ \bf \: x=\frac{22}{5},y=\frac{27}{5} }}$

3 0

3 years ago

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