Answer:
The volume of the water subtracted from the tanks is 2 × 10² m³ to
make the submarine float nor sink in the ocean ⇒ answer B
Step-by-step explanation:
* Lets talk about the relation between the mass , the volume
and the density
- Mass = Volume × Density
- The unit of the mass is kilogram
- The unit of the volume is cubic meter
- The unit of the density is Kilogram per cubic meter
* Lets find the volume to make the submarine float neutrally
∵ Mass = volume × density
∴ Volume = Mass ÷ density
∵ The mass = 8 × 10^6 kg
∵ The density of the seawater = 10³ kg/m³
∴ The volume = 8 × 10^6 ÷ 10³ = 8 × 10^(6 - 3) ⇒ (to divide numbers
with exponents and have same base, subtract the powers)
∴ The volume = 8 × 10³ m³
- The volume of the submarine never changes
∴ The submarine need to subtract:
8 × 10³ - 7.8 × 10³ = 10³ (8 - 7.8) = 0.2 × 10³ = 2 × 10² m³ from its tanks
* The volume of the water subtracted from the tanks is 2 × 10² m³ to
make the submarine float nor sink in the ocean
