Your answer is 76m.
a^2+b^2=c^2
57^2+b^2=95^2
3249+b^2=9025
b^2=5776
Take sqr on both sides and you get:
b=76m
Answer:
The volume of the concentrated 80 gallons mixture is 20 gallons
The volume of water in the 80 gallons mixture is 60 gallons
Step-by-step explanation:
The given parameters are;
The content of Container A = The cleaner
The concentration of the cleaner = 20% solution
The content of Container B = Pure water
The concentration of the desired solution = 5%
The volume of the required solution = 80 gallons
Let x represent the volume of the concentrated solution and y represent the volume of water in the 80 gallons mixture
Therefore, we have;
20/100 × x + y×0 = 5/100×80
x + y = 80
y = 80 - x
20/100 × x + (80 - x)×0 = 5/100×80
0.2·x = 4
x = 4/0.2 = 20
x = 20 gallons
y = 80 - x = 80 - 20 = 60
y = 60 gallons
The volume of the concentrated solution (80 gallons mixture) = x = 20 gallons
The volume of water in the 80 gallons mixture = y = 60 gallons.
Answer:
20 cm^2
Step-by-step explanation:
Sectioned it off and multiplied the length by the width
Answer:
13 centimeters per day.
Step-by-step explanation:
We have been given that during summer, the water level of the river increased by 78 centimeters in 6 days. We are asked to find the water level increase rate in centimeters per day.
To find the water level increase rate per day, we will divide total increase by total days as:
Therefore, the water level increase rate is 13 centimeters per day.
Answer:
I dont remember how to do this but i wish you luck, try searching on khan academy for how to do this ;)
Step-by-step explanation:
