Answer:
-12
Step-by-step explanation:
Let b = -1 and a = -3
The average rate of change =
f(b) = f(-1) = 3(-1)^2 - 5 = 3 - 5 = -2
f(a) = f(-3) = 3(-3)^2 - 5 =27 - 5 = 22
f(b) - f(a) = -2 - 22 = -24
b - a = -1 + 3 = 2
= -24/2 = -12
What is the sum of a 6-term geometric sequined if the first term is 22 and the last term is 1299078
1 answer:
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The probability that the transistor will last between 12 and 24 weeks is 0.424
X= lifetime of the transistor in weeks E(X)= 24 weeks
O,= 12 weeks
The anticipated value, variance, and distribution of the random variable X were all provided to us. Finding the parameters alpha and beta is necessary before we can discover the solutions to the difficulties.
X~gamma()
E(X)=
=
=6 weeks
V(x)=
=24/6= 4
Now we can find the solutions:
The excel formula used to create Figure one is as follows:
=gammadist(X, ,
, False)
P()
P()
P()
P= 0.424
Therefore, probability that the transistor will last between 12 and 24 weeks is 0.424
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You only need to consider the situations where 10 or 11 of the babies are girls, then subtract those probabilities from 1. This will give probability that any other number up to 9 of the babies are girls.
Use binomial theorem.
n = 11
k = 10,11
p = 1/2
Use binomial theorem.
n = 11
k = 10,11
p = 1/2