Answer:
-12
Step-by-step explanation:
Let b = -1 and a = -3
The average rate of change = 
f(b) = f(-1) = 3(-1)^2 - 5 = 3 - 5 = -2
f(a) = f(-3) = 3(-3)^2 - 5 =27 - 5 = 22
f(b) - f(a) = -2 - 22 = -24
b - a = -1 + 3 = 2
= -24/2 = -12
The probability that the transistor will last between 12 and 24 weeks is 0.424
X= lifetime of the transistor in weeks E(X)= 24 weeks
O,= 12 weeks
The anticipated value, variance, and distribution of the random variable X were all provided to us. Finding the parameters alpha and beta is necessary before we can discover the solutions to the difficulties.
X~gamma(
)
E(X)=
=
=6 weeks
V(x)=
=24/6= 4
Now we can find the solutions:
The excel formula used to create Figure one is as follows:
=gammadist(X,
,
, False)
P(
)
P(
)
P(
)
P= 0.424
Therefore, probability that the transistor will last between 12 and 24 weeks is 0.424
To learn more about probability click here:
brainly.com/question/11234923
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You only need to consider the situations where 10 or 11 of the babies are girls, then subtract those probabilities from 1. This will give probability that any other number up to 9 of the babies are girls.
Use binomial theorem.

n = 11
k = 10,11
p = 1/2
The correct answers is 0.66 or .66