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chubhunter [2.5K]
3 years ago
12

Find -7a-6B (Picture provided)

Mathematics
1 answer:
sertanlavr [38]3 years ago
7 0

Answer:

Option c

-7A-6B=\left(\begin{array}{ccc}40&-106&-32\\-46&43&25\\82&-62&-18\end{array}\right)

Step-by-step explanation:

First multiply matrix A by -7.

Then multiply the matrix B by -6.

When multiplying a matrix by a number x you must multiply each element of the matrix by x.

<em><u>Then we perform operation -7A </u></em>

-7\left(\begin{array}{ccc}-10&10&8\\-2&-1&5\\-4&8&-6\end{array}\right)=\left(\begin{array}{ccc}70&-70&-56\\14&7&-35\\28&-56&42\end{array}\right)

<u><em>Now we perform operation -6B </em></u>

-6\left(\begin{array}{ccc}5&6&-4\\10&-6&-10\\-9&1&10\end{array}\right)=\left(\begin{array}{ccc}-30&-36&24\\-60&36&60\\54&-6&-60\end{array}\right)

Now we add the resulting matrices

\left(\begin{array}{ccc}70&-70&-56\\14&7&-35\\28&-56&42\end{array}\right)+\left(\begin{array}{ccc}-30&-36&24\\-60&36&60\\54&-6&-60\end{array}\right)=\left(\begin{array}{ccc}40&-106&-32\\-46&43&25\\82&-62&-18\end{array}\right)

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The probability of making his 4th attempt is 0.77, since the probability of each attempt is independent.

The probability of making a field goal over 40 yards is 77%

Since the probability of making a field goal is independent, then the probability of succeeding in his 4th attempt does not depend on his previous attempts.

Hence, the probability of making his fourth attempt is the probability of making a field goal over 40 yards in each attempt which is 77% = 0.77

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Learn more : brainly.com/question/18153040

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Step-by-step explanation:

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Step-by-step explanation:

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Refer to the accompanying scatterplot. a. Examine the pattern of all 10 points and subjectively determine whether there appears
Alex

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Step-by-step explanation:

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Answer:

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