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Lynna [10]
2 years ago
12

Suppose that there are two types of tickets to a show: advance and same-day. Advance tickets cost $30 and same-day tickets cost

$25. For
there were 60 tickets sold in all, and the total amount paid for them was $ 1625. How many tickets of each type were sold?
performance,
X
Number of advance tickets sold:
Number of same-day tickets sold: I
6
?
Mathematics
1 answer:
Andre45 [30]2 years ago
6 0

The number of advance tickets sold is 25 and same day tickets sold is 30.

Data Given;

  • Advance Ticket = $30
  • Same-day Ticket = $25
  • Total Ticket = $60
  • Total Cost of Ticket = $1625

<h3>System of Equations</h3>

Let the number of advance ticket be represented by x

Let the number of same-day ticket be represented by y

x + y = 60\\&#10;30x + 25y = 1625

From the system of equations above, we can easily pick any to start our calculation.

Using equation (i),

x + y = 60

x = 60 - y ...equation(iii)

Put equation (iii) into equation (ii)

30x + 25y = 1625\\&#10;x = 60 - y\\&#10;30(60 - y) + 25y = 1625\\&#10;1800 - 30y + 25y = 1625\\&#10;1800 -5y = 1625\\&#10;5y = 1800 - 1625\\&#10;5y = 175\\&#10;5y/5 = 175/5\\&#10;y = 35

Put the value of y into equation (i)

x+y = 60\\&#10;x + 35 = 60\\&#10;x = 60 - 35\\&#10;x = 25

From the calculation above, the number of advance tickets sold is 25 and same-day tickets is 30.

Learn more on system of equations here;

brainly.com/question/13729904

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