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andrew-mc [135]
3 years ago
13

The salesperson in a cell phone store is telling me that the phone I'm considering has 8GB of memory, which means I can save 10,

000 photos taken with the phone's camera! Is the salesperson telling me the truth? Why or why not?
Computers and Technology
1 answer:
slega [8]3 years ago
8 0
The sale person is not telling you the truth. 
This is because, the size of an average picture on phone is about 3 megabytes. One gigabyte is equivalent to 1000 megabytes; so 8GB is equivalent to 8,000MB [Megabytes].
 If you divide 8,000MB by 3MB, which is the size of an average picture, you will have approximately 2,666 pictures. This means, you will only be able to store about 2,666 pictures on that phone compared to the 10,000 pictures the sale person is talking about.
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Answer:

#include <iostream>

#include<time.h>

using namespace std;

void sort(int a[20],int n)   //selection sort

{

   int i,j,temp;

   for(i=0;i<n;i++)        

   {

       for(j=i+1;j<n;j++)  //finds minimum element

       {

           if(a[i]>a[j])     //swaps minimum element to its right place

           {

               temp=a[i];

               a[i]=a[j];

               a[j]=temp;

           }

       }

   }

}

int main()

{

   srand(time(NULL));

   int arr[20],n=20,i;

   for(i=0;i<n;i++)

       arr[i]=rand() % 100 + 1;    //assigns random number to each array element

   cout<<"Before sorting\n";

   for(i=0;i<n;i++)

       cout<<arr[i]<<" ";   //prints array before calling sort func

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}

OUTPUT :

Please find the attachment below.

Explanation:

The program above first assigns random number from 1 to 100 to each element of array using rand(). srand(time(NULL)) is used to generate new number every time otherwise same random number will be produced at a time. Then sorting method is called in which selection sort algorithm is used.

Selection sort algorithm finds the minimum element in each pass and place it into its right position. For example - 34,54,12,5 is passed

After Pass 1 - 5  54  12  34

After Pass 2 - 5  12  54  34

After Pass 3 -  5  12  34  54

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