Answer:
4.01 version .
Explanation:
A hypertext Markup language is used for designing the web page when we added the CSS on the web page we can create the web page more efficient manner and also there is more control over the web page because we can easily call the classes of CSS.
The Hypertext Markup language version 4.01 provides greater flexibility on the web page also We can also control the page layout in a very easy manner. The appearance of the web page is good as compared to version HTML 4
Answer:
Here's ur answer
Explanation:
(i) Should consist of standardized and acceptable symbols. (ii) The symbols should be correctly used according to flowcharts rules. (iii) Should have short, clear and readable statements written inside the symbols. (iv) It must have clear one starting point and one ending point.
Answer:
the difficulty in factoring large numbers
a public key that the server and the user’s computer know
the use of prime numbers
a private key that only the server knows
Explanation:
ege 2021
Answer:
Teams are diverse.
Explanation:
Teams have great advantage in problem solving over single person. A single persons's thinking is one dimensional. He sees and analyse things according to his perspective and understanding which limits his ability to solve problems .On the other hand team consist of multiple people with multiple background and perspective. Everyone has its own thinking process and it's own perspective, there fore in teams if one person is missing some perspective someone else might be looking in to that perspective which greatly enhance teams problem solving
The recursive function would work like this: the n-th odd number is 2n-1. With each iteration, we return the sum of 2n-1 and the sum of the first n-1 odd numbers. The break case is when we have the sum of the first odd number, which is 1, and we return 1.
int recursiveOddSum(int n) {
if(2n-1==1) return 1;
return (2n-1) + recursiveOddSum(n-1);
}
To prove the correctness of this algorithm by induction, we start from the base case as usual:
by definition of the break case, and 1 is indeed the sum of the first odd number (it is a degenerate sum of only one term).
Now we can assume that 
returns indeed the sum of the first n-1 odd numbers, and we have to proof that 
returns the sum of the first n odd numbers. By the recursive logic, we have
and by induction, is the sum of the first n-1 odd numbers, and 2n-1 is the n-th odd number. So, is the sum of the first n odd numbers, as required:
