6 numbers per cube
if one is a 1, then the other one has to be a 2, 4 or 6 to be an odd sum
1+2=3, 1+4=5,1+6=7
since there are 3 numbers you can get that would be a 3/6 ( reduce to 1/2) probability
so 1/2 probability
Answer:
Need help with using the graph to find the numbers
Assignment is about evaluating composition of functions from graphs anything helps
Answer:
E) 1 and 2
Step-by-step explanation:
We are given that there are two integers (s and t) and they are factors of another integer (n). For example if s = 3 and t = 2, we can have n = 6.
Thus:
n^(st) = 6^(2*3) = 6^6 = (2^6)(3^6)
For the first condition: s^t = 3^2 is a factor of (2^6)(3^6)
For the second condition: (st)^2 = (3*2)^2 = 6^2 is a factor of 6^6
For the third condition: s+t = 3+2 = 5 is not a factor of 6^6 or (2^6)(3^6)
Therefore, only 1 and 2 are factors of n^(st)
Answer:
26
Step-by-step explanation:
To evaluate this expression, all we have to do is substitute the given values of the variables into the expression. That is, replace every 
in the expression with a 
and every 
in the expression with a 5.
Doing so, we get:
(Substitute given values into the expression)
(Evaluate exponential term)
(Add)
Hope this helps!
