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Pie
3 years ago
14

I need help! -4y-4+(-3)​

Mathematics
1 answer:
faltersainse [42]3 years ago
3 0

Answer:

-4y-7

Step-by-step explanation:

-4y-4-3

-4y-7

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Determine the unknown measures of the triangle shown. Round to the nearest tenth, if necessary
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4 years ago
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A scientist needs 10 liters of a 20% acid solution for an experiment, but she has only a 5% solution and a 40% solution. To the
tamaranim1 [39]

Answer:

The volume of 40% solution= 4.3L

The volume of 5% solution= 10L - 4.3L= 5.7L

Step-by-step explanation:

From the given information:

Let consider  x to be the of volume 40% solution

therefore the volume of 5% is said to be:

10 L= 40% solution volume + 5% solution volume

10 L= (x + 5%) solution volume

making 5% solution volume the subject; we have

5% solution volume= 10 L - x

To estimate the value of the volume, we now have:

Volume  of 20% × Concentration of  20%= (Volume of 40%  × concentration40%) + (Volume of 5% × Concentration of 5% )

∴

10L  ×  20%= (x) L × 35% + 10 L × 5%

(x) L × 35 = 10L × 20 - 10 L × 5 = 10 L × 15

x L = 10L \times \dfrac{15}{35}

x = 4.28 L

x \simeq 4.3L

∴

The volume of 40% solution= 4.3L

The volume of 5% solution= 10L - 4.3L= 5.7L

8 0
4 years ago
Help<br> the question is in the pic below
Arte-miy333 [17]
The answer is 2.

Since the number below the first shape is 1, you would have to multiply by 2 to get to 2 (which is the number under the second shape).
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3 years ago
On a particular map, 3 inches on the map equates to 10 miles in real life. If you know that the real-life distance between two b
Yakvenalex [24]

Answer:

15\dfrac{39}{40} $ inches

Step-by-step explanation:

On the map, 3 inches = 10 miles in real life.

Therefore:

10 miles: 3 Inches

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If the real-life distance between two buildings is 53.25 miles

Distance on the map

\dfrac{3}{10}$ X 53.25 inches\\=15.975 inches

=15\dfrac{39}{40} $ inches

The distance between the two buildings on the map is therefore: 15\dfrac{39}{40} $ inches

3 0
3 years ago
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