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notka56 [123]
3 years ago
9

On a particular map, 3 inches on the map equates to 10 miles in real life. If you know that the real-life distance between two b

uildings on the map is 53.25 miles, what would the distance between the buildings be (in inches) on the map, expressed as a fraction?
Mathematics
1 answer:
Yakvenalex [24]3 years ago
3 0

Answer:

15\dfrac{39}{40} $ inches

Step-by-step explanation:

On the map, 3 inches = 10 miles in real life.

Therefore:

10 miles: 3 Inches

1$ miles rep $ \dfrac{3}{10}$ inches

If the real-life distance between two buildings is 53.25 miles

Distance on the map

\dfrac{3}{10}$ X 53.25 inches\\=15.975 inches

=15\dfrac{39}{40} $ inches

The distance between the two buildings on the map is therefore: 15\dfrac{39}{40} $ inches

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\qquad\qquad\huge\underline{{\sf Answer}}♨

Let's solve ~

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