Question

Two passenger trains traveling in opposite directions meet and pass each other. Each train is 1/12 mi long and is traveling 50 mph. How many seconds after the front cars of the trains meet will their rear cars pass each other?

Answer 1

Answer:

6 seconds

Step-by-step explanation:

Total distance between the 2 rear cars = $\\\frac{1}{12} + \frac{1}{12} = \frac{1}{6}\\\\\\\\\\Relative speed of the trains = 50 + 50 = 100 mphT = \frac{Distance}{Speed} = \frac{1}{6} * \frac{1}{100} = \frac{1}{600} hours\\T = \frac{1}{600} hours or \frac{3600}{600} = 6 seconds$