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goldfiish [28.3K]
3 years ago
8

Which equation below is a direct variation?

Mathematics
1 answer:
masya89 [10]3 years ago
5 0
Direct variation is of the form y = kx where k is a constant

So its A
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Resolva os sistemas abaixo <br> 2x+3y=80<br> 3x+2y=70<br><br><br><br> X=8y<br> X+4y=480
timurjin [86]
Solución 1: 2(x) + 3(y) = 80
solución 2: 3(x) + 2(y) = 70

3(y) + 2(x) = 80
2(y) + 3(x) = 70

2y = -3x + 70
y = -3x÷2 + 35

2x + 3(-3x÷ 2+35) = 80  
-5x÷2 = -25  
-5x = -50

5x = 50   
x-intercept: 10 
x = 10  
y = -3x÷ 2+35

  y = -(3÷2)(10)+35 = 20 

x-interpcet: 10
y-intercept: 20
~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~
solución: x - 8y = 0
solución x + 4y = 480

-8y + x = 0
4y + x = 480

x-intercept (solución 2)
x = -4x + 480

x-intercept (solución 1)
4y + 180 - 8y = 0
-12y = 480

y-intercept: 40
x-intercept: 320


Buena Suerte!


7 0
3 years ago
If 1 cm represents 35 miles what is 1.25 cm in miles?
lapo4ka [179]

Answer:

43.75 miles

Step-by-step explanation:

You divide the 35 by 4 and then just add it to the original distance of 35 miles. 35/4=8.75

8.75+35=43.75

8 0
3 years ago
A function, F(x), is shown below.
Maksim231197 [3]

Answer:

  range of f(x) = [-4, -2) ∪ [2, 8)

  a+b+c+d = -4

Step-by-step explanation:

The graph is attached. The range is the vertical extent of the function. It is defined at f(0) = -4 and f(2) = 2.

The limits f(2-) and f(4-) are -2 and 8, respectively, so the graph has open circles there. These are the ends of the two half-open intervals that make up the range of the function.

The portion of the graph in the domain [4, 7) is included in the range [2, 8), so no special treatment is needed for that piece of the function.

7 0
3 years ago
Fatores 2m^4 - 18n^6
exis [7]
2m⁴ - 18n⁶
2(m⁴) - 2(9n⁶)
2(m⁴ - 9n⁶)
2(m⁴ - 3m²n³ + 3m²n³ - 9n⁶)
2[m²(m²) - m²(3n³) + 3n³(m²) - 3n³(3n³)]
2[m²(m² - 3n³) + 3n³(m² - 3n³)]
2(m² + 3n³)(m² - 3n³)
6 0
3 years ago
Which data set has an outlier? 25, 36, 44, 51, 62, 77 3, 3, 3, 7, 9, 9, 10, 14 8, 17, 18, 20, 20, 21, 23, 26, 31, 39 63, 65, 66,
umka21 [38]

It's hard to tell where one set ends and the next starts.  I think it's

A. 25, 36, 44, 51, 62, 77

B. 3, 3, 3, 7, 9, 9, 10, 14

C. 8, 17, 18, 20, 20, 21, 23, 26, 31, 39

D. 63, 65, 66, 69, 71, 78, 80, 81, 82, 82
Let's go through them.

A. 25, 36, 44, 51, 62, 77

That looks OK, standard deviation around 20, mean around 50, points with 2 standard deviations of the mean.

B. 3, 3, 3, 7, 9, 9, 10, 14

Average around 7, sigma around 4, within 2 sigma, seems ok.

C. 8, 17, 18, 20, 20, 21, 23, 26, 31, 39

Average around 20, sigma around 8, that 39 is hanging out there past two sigma.  Let's reserve judgement and compare to the next one.


D. 63, 65, 66, 69, 71, 78, 80, 81, 82, 82

Average around 74, sigma 8, seems very tight.

I guess we conclude C has the outlier 39.  That one doesn't seem like much of an outlier to me; I was looking for a lone point hanging out at five or six sigma.  



3 0
4 years ago
Read 2 more answers
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