State and prove exterior angle property of triangle

Mathematics

2 answers:

zhenek [66]3 years ago

7 0

Answer:

Step-by-step explanation:

An exterior angle of a triangle is equal to the sum of its interior opposite angles.If any side of a triangle is extended, then the exterior angle so formed is the sum of the two opposite interior angles of the triangle. In the given figure, the side BC of angle ABC is extended.

Tju [1.3M]3 years ago

7 0

The exterior angle property ty of a triangle states that all the exterior angles are equal to 360 degrees

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Here we're given
p=0.10 [ success = defective ]
n=3

(a) x=0
$P(x)=C(n,x)p^x(1-p)^{n-x}$
$=C(3,0)0.1^0(1-0.1)^{3-0}$
$=1(1)(0.729)$
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(b) x=2
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$=C(3,2)0.1^2(1-0.1)^{3-2}$
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$=0.027$

(c) x ≥ 2
$P(x)=\sum_{x=2}^3C(n,x)p^x(1-p)^{n-x}$
$=P(2)+P(3)$
$=C(n,2)p^2(1-p)^{n-2}+C(n,3)p^3(1-p)^{n-3}$
$=C(3,2)0.1^2(1-0.1)^{3-2}+C(3,3)0.1^3(1-0.1)^{3-3}$
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$=0.028$

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