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son4ous [18]
3 years ago
10

An object be a moving at the starting (0,0) on the graph. Average speed in miles per hour of the object for an entire trip five

hours is...

Mathematics
1 answer:
Vikki [24]3 years ago
4 0

Answer: 17 miles per hour.

Step-by-step explanation:

1. To solve this problem you must apply the following formula:

S=Δx/Δt

Where Δx is the position variation and Δt is the time variation.

2. Then, based on the graph shown attached, you have:

S=\frac{20mi+20mi+30mi+15mi}{1h+1h+1h+2h}

3. Therefore, you have that the result is:

S=17mi/h

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A number from 0 to 9 is randomly selected and then a letter from A to D is randomly selected. What is the probability that the n
maw [93]

Answer:

3/20

Step-by-step explanation:

First we must get the total amount of possibilities.

We have ten numbers(0 included) and 4 letters. 10 * 4 = 40, so 40 total possibilities.

Now, let's see how many possibilities we can have for this.

Consonants in the 4 letters are B, C, D. This means we have 3 possibilities, but we ACTUALLy have 6 since it could b then 3, or 3 then b for all the letters.

So, we end up having 6/40 which simplifies in to 3/20

7 0
3 years ago
The International Air Transport Association surveys business travelers to develop quality ratings for transatlantic gateway airp
motikmotik

Answer:

The 95% confidence interval for the population mean rating is (5.73, 6.95).

Step-by-step explanation:

We start by calculating the mean and standard deviation of the sample:

M=\dfrac{1}{n}\sum_{i=1}^n\,x_i\\\\\\M=\dfrac{1}{50}(6+4+6+. . .+6)\\\\\\M=\dfrac{317}{50}\\\\\\M=6.34\\\\\\s=\sqrt{\dfrac{1}{n-1}\sum_{i=1}^n\,(x_i-M)^2}\\\\\\s=\sqrt{\dfrac{1}{49}((6-6.34)^2+(4-6.34)^2+(6-6.34)^2+. . . +(6-6.34)^2)}\\\\\\s=\sqrt{\dfrac{229.22}{49}}\\\\\\s=\sqrt{4.68}=2.16\\\\\\

We have to calculate a 95% confidence interval for the mean.

The population standard deviation is not known, so we have to estimate it from the sample standard deviation and use a t-students distribution to calculate the critical value.

The sample mean is M=6.34.

The sample size is N=50.

When σ is not known, s divided by the square root of N is used as an estimate of σM:

s_M=\dfrac{s}{\sqrt{N}}=\dfrac{2.16}{\sqrt{50}}=\dfrac{2.16}{7.071}=0.305

The degrees of freedom for this sample size are:

df=n-1=50-1=49

The t-value for a 95% confidence interval and 49 degrees of freedom is t=2.01.

The margin of error (MOE) can be calculated as:

MOE=t\cdot s_M=2.01 \cdot 0.305=0.61

Then, the lower and upper bounds of the confidence interval are:

LL=M-t \cdot s_M = 6.34-0.61=5.73\\\\UL=M+t \cdot s_M = 6.34+0.61=6.95

The 95% confidence interval for the mean is (5.73, 6.95).

4 0
3 years ago
Hey can someone help me ?
morpeh [17]
Sure what do u need help with?
6 0
2 years ago
Need help ASAP I don’t understand what to do because x = 2 and y = 3 but they don’t divide into each other evenly so is it a dec
Artyom0805 [142]

Answer:

You can have it as a decimal (0.6 repeatings), or you can have it as a fraction. It would be easier to keep it as a fraction.

3 0
2 years ago
What is the relationship between the two shapes?
vova2212 [387]

Answer  

its b

Step-by-step explanation:

6 0
3 years ago
Read 2 more answers
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