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Vikentia [17]
3 years ago
9

Please help! 50 points and i'll give brainliest!

Mathematics
2 answers:
igomit [66]3 years ago
8 0

Answer:

It's 70.

Step-by-step explanation:

I realllllllly hope this helps and I realllllly hope you give me brainliest.

Nitella [24]3 years ago
3 0

if im correct its 70

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3 years ago
A rack of 15 billiard balls is shown. If one ball is selected at​ random, determine the odds against it containing a number grea
andre [41]

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  • An odd is the <u>number of desired outcomes divided by the number of non-desired outcomes</u>.

In the rack, there are 15 balls, numbered from 1 to 15. Of those, <u>6 are less than 7</u>(against it containing a number greater than or equal to 7 is equivalent to it containing a number less than 7), thus:

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  • There are 9 non-desired outcomes.

The odd is:

\frac{6}{9} = \frac{2}{3}

The odds against it containing a number greater than or equal to 7 is \frac{2}{3}.

A similar problem is given at brainly.com/question/21094006

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