Answer:
Time t = 2 seconds
It will reach the maximum height after 2 seconds
Completed question;
Amir stands on a balcony and throws a ball to his dog who is at ground level. The ball's height, in meters above the ground, after t seconds that Amir has thrown the ball is given by:
H (t) = -(t-2)^2+9
many seconds after being thrown will the ball reach its maximum height?
Step-by-step explanation:
The equation of the height!
h(t) = -(t-2)^2 + 9 = -(t^2 -4t +4) + 9
h(t) = -t^2 +4t -4+9
h(t) = -t^2 + 4t +5
The maximum height is at dh/dt = 0
dh/dt = -2t +4 = 0
2t = 4
t = 4/2 = 2
Time t = 2 seconds
It will reach the maximum height after 2 seconds
Answer:
Well since we don't know what X or Y is, then we can't answer this question.
Step-by-step explanation:
Answer:
y = 3x - 11
Step-by-step explanation:
Step 1:
y = mx + b Slope Intercept Form
Step 2:
y = 3x + b Input Slope
Step 3:
- 5 = 3 ( 2 ) + b Input x and y values
Step 4:
- 5 = 6 + b Multiply
Step 5:
- 11 = b Subtract 6 on both sides
Answer:
y = 3x - 11
Hope This Helps :)
Answer: 5 7\8
Step-by-step explanation:
