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mihalych1998 [28]
3 years ago
14

Divide using synthetic division. (r^4 - 3r^3 - 15r^2 + 7r + 2) / (r + 3)

Mathematics
2 answers:
boyakko [2]3 years ago
8 0

Answer:

jdjkajd

Step-by-step explanation:

jdjdhs

nydimaria [60]3 years ago
3 0

Answer:

Step-by-step explanation:

hello :

look this solution

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Find the product (3x+8)(x-4)
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Answer:

3x^{2} - 4x - 32

Step-by-step explanation:

(3x+8)(x-4)

=3x^{2} -12x + 8x -32

=3x^{2} - 4x - 32

7 0
3 years ago
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Fred is making a bouquet of carnations and roses. The carnations cost $5.25 in all. The roses cost $1.68 each. How many roses di
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Answer:

8 roses

Step-by-step explanation:

First start by subtracting $18.69 by $5.25 because you already know how much the carnations cost and how much the bouquet cost in all. When you subtract 18.69 by 5.25 you should get $13.44. If each rose cost $1.68 then divide 13.44 by 1.68 to get the amount of roses in the bouquet.

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3 years ago
Adison earned $25 mowing her neighbor's lawn. Then she loaned her friend $13 and got $50 from her grandma for her birthday. She
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She started off with 24
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David has a bag of coins. The bag contains 7 dimes, 2 nickels, and 6 pennies. He will randomly select 2 coins from the bag one a
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7 out of 17 coin in the bag
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3 years ago
Listed below are speeds (mi/h) measured from southbound traffic on I-280 near Cupertino, California (based on data from SigAlert
adell [148]

Answer:

Option (B) is the correct answer to the following question.

Step-by-step explanation:

Step-1: We have to find the Mean of the series.

The series is Given in the question 62 61 61 57 61 54 59 58 59 69 60 67.

Mean(\overline{x})=\frac{62+61+61+57+61+54+59+58+59+69+60+67}{12} = 60.67

Step-2: We have to find the Standard Deviation.

Let Standard Deviation be x.

Formula of Standard Deviation is: s= \sqrt{\frac{\sum(x_{i}+\overline{x})}{n-1}}

Put value in formula of Standard Deviation,

s= \sqrt{\frac{(62+60.67)^{2}+(61+60.67)^{2}+(61+60.67)^{2}+(57+60.67)^{2}+....(67+60.67)^{2}}{n-1}} = 40.75

Step-3: Then, we have to find the critical value by chi-square.

X_{1-\alpha/2}^{2}=3.82

X_{1-\alpha/2}^{2}=21.92

Then, find the confidence interval which is 95%.

\sqrt{\frac{(n-1).s^2}{X_{\alpha/2}^{2}} } = \sqrt{\frac{12-1}{21.92}.(4.075)^2 }\approx2.8868 \\ i.e 2.9

\sqrt{\frac{(n-1).s^2}{X_{\alpha/2}^{2}} } = \sqrt{\frac{12-1}{3.816}.(4.075)^2 }\approx6.9188 \\ i.e 6.9

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3 years ago
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