<h3>Given</h3>
z = 3
2y +z = 1
2x +3y +2z = 13
<h3>Find</h3>
x, y, z
<h3>Solution</h3>
... z = 3 is given
Substitute that into the second equation.
... 2y + 3 = 1
... 2y = -2 . . . . . subtract 3
... y = -1 . . . . . . . divide by the coefficient of y
Substitute these two solutions into the third equation.
... 2x +3(-1) +2(3) = 13
... 2x = 10 . . . . . . . . . . . . collect terms, subtract 3
... x = 5 . . . . . . . . . . . . . . divide by the coefficient of x
The variable values are: x = 5, y = -1, z = 3
The best estimate would be one kilogram since one gram is about the mass of a paperclip.
2/9 of H?... , um I think
Answer:
Step-by-step explanation:
What is the equation?
You need to replace all A with 3 and all c with 12. If I had the equation, I'd be glad to help further.
Well you can times both numerator and denominator 1/6 by 2 and get 2/12 so then add 2/12 and 11/12 which equals 13/12 and rounded up would be 1 1/12 have a good day
