Answer:
19 seconds.
Step-by-step explanation:
Given that the clock was exactly on time at 7am, and at 1pm the clock was 228 seconds late, to determine, at that rate, how slow was the clock half an hour, the following calculation must be performed:
1 PM = 13:00
13 - 7 = 6
228/6 = 38
38/2 = 19
Thus, every half hour the clock is delayed 19 seconds.
Answer:
I have already answered this in your last question:)
Answer:
C
Step-by-step explanation:
Mean: 9+6+18+2+13+3+5= 56/7 = 8
Median: 2,3,5,6,9,13,18 the middle number is 6
mode:none
This is exponential growth/decay type problem...
F=Ir^t, F=final value, I=initial value, r=rate, t=time, in this case I=1250 and r=(1-.045)=0.955 so
F=1250(.955)^t and we want to find t for when F=800
800=1250(.955)^t
.64=.955^t take the natural log of both sides...
ln.64=t ln.955
t=(ln.64)/ln.995
t≈9.69 weeks
t≈9.69 weeks (to nearest hundredth of a week)
