Question

Print "Censored" if userInput contains the word "darn", else print userInput. End with newline. Ex: If userInput is "That darn cat.", then output is:
Censored


Ex: If userInput is "Dang, that was scary!", then output is:


Dang, that was scary!


Note: If the submitted code has an out-of-range access, the system will stop running the code after a few seconds, and report "Program end never reached." The system doesn't print the test case that caused the reported message.


#include


#include


using namespace std;


int main() {


string userInput;


getline(cin, userInput);


int isPresent = userInput.find("darn");


if (isPresent > 0){


cout << "Censored" << endl; /* Your solution goes here */


return 0;


}

Answer 1

Answer:

The Java code is given below

Explanation:

import java.util.*;

public class CensoredWords {

public static void main(String args[]) {

Scanner scnr=new Scanner(System.in);

String userInput;

System.out.println("Enter String: ");

userInput=scnr.nextLine();

int res=userInput.indexOf("darn");

if(res == - 1) {

System.out.println(userInput);

} else {

System.out.println("Censored");

}

}

}