Which product is negative?

2 answers:

8 0

$\text{You're trying to find which product is negative}\\\\\text{You would find your answer by multiplying}\\\\\text{Multiply:}\\\\1.\\-3\cdot-2\cdot-4\cdot-7= 168\\\\2.\\-2\cdot-7\cdot12\cdot4=672\\\\3.\\-6\cdot-7\cdot-8\cdot0=0\\\\4\cdot-9\cdot-3\cdot-1=-108\\\\\boxed{\text{Answer: 4: 4 *(-9)*(-3)*(-1)}}$

Lady_Fox [76]3 years ago

7 0

2 is negative. Hope this helps:)

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If angle a has the terminal ray that falls in the fourth quadrant and cosine a equals 5/9 then determine the value of sin a in s

Tema [17]

Answer: $-\dfrac{2\sqrt{14}}{9}$

Step-by-step explanation:

Given

$\cos a=\dfrac{5}{9}$

$a$ lies in the fourth quadrant

So, sine must be negative in the fourth quadrant

Using identity $\sin ^2 x+\cos^2 x=1$ to find sine value

$\Rightarrow \sin^2 a=1-\dfrac{5^2}{9^2}$

$\\\\\Rightarrow \sin^2 a=1-\dfrac{25}{81}\\\\\\\Rightarrow \sin^2 a=\dfrac{56}{81}\\\\\\\Rightarrow \sin a=-\sqrt{\dfrac{56}{81}}\\\\\\\Rightarrow \sin a=-\dfrac{2\sqrt{14}}{9}$