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4 years ago

In a right triangle, the adjacent side / the opposite side is: A. cosine B. cotangent C. sine D. tangent

Mathematics

2 answers:

REY [17]4 years ago

6 0

Answer:

Option B

Step-by-step explanation:

Cot θ = $\frac{adjacent}{opposite}$

katrin2010 [14]4 years ago

3 0

Answer:

B. cotangent

Step-by-step explanation:

Just took the test!!

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PLS HELP<br> I BEG youuuu

Marina CMI [18]

Answer:

19 square units

Step-by-step explanation:

There are a LOT of different ways to solve this problem, most of which involve breaking up the shape into smaller shapes. For me, it’s easier to draw a rectangle around the figure, find that area, and then subtract the four areas not in the figure.

Rectangle: would be from -3 to 3 (6) and -2 to 4 (6). 6x6=36

The four missing triangles:

AB = 1/2(3)(2)=3

BC = 1/2(2)(4)=4

CD = 1/2(2)(4)=4

DA = 1/2(4)(3)=6

6+4+4+3=17

36-17=19

7 0

4 years ago

A + b + c = 180 <br> b = 3a <br> c = 5a<br> Whats B

NikAS [45]

Sub

b=3a so put 3a for every b
c=5a so put 5a for every c
a+3a+5a=180
9a=180
divide 9 both sides
a=20

b=3a
b=3(20)
b=60

4 0

4 years ago

Read 2 more answers

5.93e-5 in standard form

Nadusha1986 [10]

it would be written as 11.11941124 hope it helps.pls give brainliest! :p

3 0

4 years ago

A picture frame (see figure) has a total perimeter of 3 feet. The width of the frame is 0.64 times its length. Find the dimensio

Naya [18.7K]

Answer:

$\approx 0.59\text{ ft by }0.91\text{ ft}$

Step-by-step explanation:

Let $\ell$ represent the length of the rectangle. The width can be represented as $0.64\ell$ .

The perimeter of a rectangle with lengths $l$ and $w$ is given by $p=2l+2w$ .

Thus, we have:

$2\ell+2(0.64\ell)=3,\\2\ell +1.28\ell=3,\\3.28\ell=3,\\\ell=0.91463414634\approx 0.91$

The width is then $0.64(0.91463414634)=0.58536585365\approx 0.59$ .

8 0

3 years ago

A sample of 64 was taken from a population, with the mean of the sample being 119 and the standard deviation of the sample being

Fofino [41]

We have the sample size, sample mean and the sample standard deviation. Since the population standard deviation is not know, we will use t-distribution to find the confidence interval.

The critical t value for 95% confidence interval and 63 degrees of freedom is 1.998.

The 95% confidence for the population mean will be:

$(119-1.998 *\frac{16}{ \sqrt{64} } ,119+1.998 *\frac{16}{ \sqrt{64} }) \\ \\ 
=(115.004, 122.996) \\ \\=(115,123)$

Thus, the 95% confidence interval for the population mean will be (115,123)

So, option A is the correct answer

6 0

3 years ago