Answer:
10 ft, 14 ft
Step-by-step explanation:
Let b represent the length of the shorter base. Then the longer one is b+4 and the area is ...
A = (1/2)(b1 +b2)h
120 = (1/2)(b +(b+4))(10) . . . . use given values
12 = b+2 . . . . . . divide by 10, simplify
10 = b
14 = b+4
The measurements of the two bases are 10 ft and 14 ft.
<u>8 and 4:</u>
Multiples of 8: 8, 16, 24
Multiples of 4: 4, 8, 12, 16
<u>8 and 6:</u>
Multiples of 6: 6, 12, 18, 24
<u>8</u><u> </u><u>and</u><u> </u><u>10</u><u>:</u>
Multiples of 8: 8, 16, 24, 32, 40
Multiples of 10: 10, 20, 30, 40
c=10
pythagreom theroem
c (hypotenuse) =
plug in values for a and b
c=
2 15 sorry po kung mali
Wala pong step by step
x=7, y=16
2x+5=x+12
2x=x+7
x=7
y-4=x+5
y-4=12
y=16
It is a solution
8d+6= -8d-186
Add 8d to each side
8d+8d+6= -8d+8d-186
16d +6 = -186
Subtract 6 from each side
16d +6-6 = -186 -6
16d = -192
Divide each side by 16
16d/16 = -192/16
d = -12