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Debora [2.8K]
3 years ago
7

Find the lengths of the bases of the trapezoid with a height of 10 ft. One base is 4ft longer than the other bases. The area is

120 square feet. Check the measurement of the TWO bases.
24
20
14
28
10
18
Mathematics
1 answer:
liq [111]3 years ago
5 0

Answer:

  10 ft, 14 ft

Step-by-step explanation:

Let b represent the length of the shorter base. Then the longer one is b+4 and the area is ...

  A = (1/2)(b1 +b2)h

  120 = (1/2)(b +(b+4))(10) . . . . use given values

  12 = b+2 . . . . . . divide by 10, simplify

  10 = b

  14 = b+4

The measurements of the two bases are 10 ft and 14 ft.

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BlackZzzverrR [31]

Answer:

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4 0
3 years ago
Kamal wrote the augmented matrix below to represent a system of equations
ra1l [238]

Consider the operation is R_2\to -3R_2.

Given:

The augmented matrix below represents a system of equations.

\left[\left.\begin{matrix}1&0&1\\1&3&-1\\3&2&0\end{matrix}\right|\begin{matrix}-1\\-9\\-2\end{matrix}\right]

To find:

Matrix results from the operation R_2\to -3R_2.

Step-by-step explanation:

We have,

\left[\left.\begin{matrix}1&0&1\\1&3&-1\\3&2&0\end{matrix}\right|\begin{matrix}-1\\-9\\-2\end{matrix}\right]

After applying R_2\to -3R_2, we get

\left[\left.\begin{matrix}1&0&1\\-3(1)&-3(3)&-3(-1)\\3&2&0\end{matrix}\right|\begin{matrix}-1\\-3(-9)\\-2\end{matrix}\right]

\left[\left.\begin{matrix}1&0&1\\-3&-9&3\\3&2&0\end{matrix}\right|\begin{matrix}-1\\27\\-2\end{matrix}\right]

Therefore, the correct option is A.

3 0
3 years ago
Cuál es el resultado de |-15| x (-5)​
notka56 [123]

Answer:

\frac{15}{x^5}

Step-by-step explanation:

\left|-15\right|x^{-5}

Step 1: Apply exponent rule: \:a^{-b}=\frac{1}{a^b}

=\left|-15\right|\frac{1}{x^5}

Step 2: Multiply fractions: a\cdot \frac{b}{c}=\frac{a\:\cdot \:b}{c}

=\frac{1\cdot \left|-15\right|}{x^5}

Step 3: Simplify

=\frac{15}{x^5}

The result is =\frac{15}{x^5}

<u>Spanish/Espanól</u>

Respuesta:

\frac{15}{x^5}

Explicación paso a paso:

\left|-15\right|x^{-5}

Paso 1: aplique la regla del exponente: \:a^{-b}=\frac{1}{a^b}

=\left|-15\right|\frac{1}{x^5}

Paso 2: multiplica fracciones: a\cdot \frac{b}{c}=\frac{a\:\cdot \:b}{c}

=\frac{1\cdot \left|-15\right|}{x^5}

Paso 3: simplifica

=\frac{15}{x^5}

El resultado es =\frac{15}{x^5}

7 0
3 years ago
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Answer:

Step-by-step explanation:

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x=12

<pst=129

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3 years ago
The height of a apple
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Three inches..........
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