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natulia [17]
2 years ago
11

Solve for b . Simplify your answer as much as possible. 40=25b

Mathematics
1 answer:
Anit [1.1K]2 years ago
3 0
8/5
I divided from both sides and flip the equation
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Irina18 [472]

Answer:

Step-by-step explanation:

5 0
2 years ago
Which equation could be solved using the graph above?
nevsk [136]

Answer:

Option 3

Step-by-step explanation:

we are given the graph of a parabola

with vertex at (0,-1) and symmetrical about y axis and also open up.

Hence the equation of the graph would be transformation of y=x^2

by a vertical shift of 1 unit down.

So new equation after transformation would be

y+1=x^2

Ory=x^2-1

Hence option 3 is right choice.

Verify:

Put Solving the equation we get

x^2=1

x=±1

In the graph x intercepts are the same as -1 and 1

Hence our answer is right.

8 0
3 years ago
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Can someone please help:(<br> 20 points??
77julia77 [94]

the answer might me B, not enough information to determine. if not that then D

3 0
3 years ago
There are 158 students registered for American History classes. There are twice as many students registered in second period as
Margarita [4]

There are 28 students in first period and 56 students in sceond period and 74 students in third period

<em><u>Solution:</u></em>

Let the number of students in first period be "x"

Let the number of students in second period be "y"

Let the number of students in third period be "z"

<em><u>There are 158 students registered for American History classes.</u></em>

Therefore,

x + y + z = 158 ---------- eqn 1

<em><u>There are twice as many students registered in second period as first period</u></em>

number of students in second period = twice of number of students in first period

y = 2x ------- eqn 2

<em><u>There are 10 less than three times as many students in third period as in first period</u></em>

number of students in third period = 3 times number of students in first period - 10

z = 3x - 10 ------ eqn 3

<em><u>Substitute eqn 2 and eqn 3 in eqn 1</u></em>

x + 2x + 3x - 10 = 158

6x = 168

<h3>x = 28</h3>

<em><u>Substitute x = 28 in eqn 2</u></em>

y = 2(28)

<h3>y = 56</h3>

<em><u>Substitute x = 28 in eqn 3</u></em>

z = 3(28) - 10

z = 84 - 10

<h3>z = 74</h3>

Thus there are 28 students in first period and 56 students in sceond period and 74 students in third period

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2 years ago
Solve 5X30 draw a picture
emmasim [6.3K]
150 is your correct answer 
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2 years ago
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