Figure A best represents it because if you add 576 and 49 you get 625, which shows the theorem of a^2+b^2=c^2.
The answer to this problem is C, because the difference between 500 and 900 is 400 and the difference between 150 and 200 is 50 meaning P(x)=-0.25x^2-400x+50
Answer: x=5√3(you've got it correct!)
y=15
In∆ADC,
Cos 60°=DC/10
DC=5
y=20-5
y=15
Answer:
Step-by-step explanation:
The attachment will help you with your question:
Using the relation between velocity, distance and time, it is found that he traveled 281.25 km by bus and 1618.75 km by plane.
<h3>What is the
relation between velocity, distance and time?</h3>
Velocity is distance divided by time, that is:
In this problem, first he traveled a distance of d km by bus, with an average speed of 60 km/h and a time of t, hence:
Then, by plane, he traveled a distance of 1900 - d km, with an average speed of 700 km/h and a time of 7 - t, hence:
Since d = 60t, we have that:
Hence:
d = 60t = 60 x 4.6875 = 281.25 km
1900 - d = 1900 - 281.25 = 1618.75 km
He traveled 281.25 km by bus and 1618.75 km by plane.
More can be learned about the relation between velocity, distance and time at brainly.com/question/24316569