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Klio2033 [76]
3 years ago
12

Evaluate 8-m/n +m when m=8 and n=2

Mathematics
1 answer:
RUDIKE [14]3 years ago
3 0
Substitute the answer: therefore, 8-8/2+8= 0/10 in fraction form, but as you feather simplify 0 divide by 10 you'll get the answer as 0.
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10m-3(2m-9)=9(m-1)+1
Studentka2010 [4]
Reorder the terms 10m+(-9*-3+2m*-3)=9(m+-1)+1
combine like terms 10m+-6m=4m 27+4m = 9(m+-1)+1
solve 27+4m=-8+9m
m=7

3 0
3 years ago
Help plssss I’m trying to finish this diagnostics test
Allushta [10]

Answer: 5 Seconds

Step-by-step explanation: Given the equation of the height expressed ad;

h(t) = - 16t^2 + initial height

Given that initial height = 400feet

h(t) = - 16t^2 + 400

The waste will hit the ground at when h(t) = 0

substitute

0 =  - 16t^2 + 400

16t^2 = 400

t² = 400/16

t² = 25

t = √25

t = 5secs

4 0
2 years ago
Can someone plsss help me
balu736 [363]

Answer:

y = -5/3 x + 40

Step-by-step explanation:

The general form is y = ax + b, where a is the slope and b is the y intercept.

So immediately you can see that b must be 40, since the line crosses the y axis at 40.

The slope can be calculated by finding two "nice" points on the line that are also grid lines.

How about (0,40) and (6, 30).

Then, calculate the slope by dividing the y difference by the x difference:

(30-40)/(6-0) = -10/6 = -5/3

So C must be the answer.

6 0
2 years ago
The figures are similar. The ratio of the perimeters is 8 : 5. Find X
vova2212 [387]

Answer:

Two figures that have the same shape are said to be similar. When two figures are similar, the ratios of the lengths of their corresponding sides are equal. To determine if the triangles below are similar, compare their corresponding sides.

3 0
2 years ago
Given a function I and a subset A of its domain, let I(A) represent the range of lover the set A; that is, I(A) = {I(x) : x E A}
Ede4ka [16]

Step-by-step explanation:

(a)

Using the definition given from the problem

f(A) = \{x^2  \, : \, x \in [0,2]\} = [0,4]\\f(B) = \{x^2  \, : \, x \in [1,4]\} = [1,16]\\f(A) \cap f(B) = [1,4]  = f(A \cap B)\\

Therefore it is true for intersection. Now for union, we have that

A \cup B = [0,4]\\f(A\cup B ) = [0,16]\\f(A) = [0,4]\\f(B)= [1,16]\\f(A) \cup f(B) = [0,16]

Therefore, for this case, it would be true that f(A\cup B) = f(A)\cup f(B).

(b)

1 is not a set.

(c)

To begin with  

A\cap B \subset A,B

Therefore

g(A\cap B) \subset g(A) \cap g(B)

Now, given an element of g(A) \cap g(B) it will belong to both sets, therefore it also belongs to g(A\cap B), and you would have that

g(A)\cap g(B) \subset  g(A \cap B), therefore  g(A)\cap g(B)  =  g(A \cap B).

(d)

To begin with A,B  \subset A \cup B, therefore

g(A) \cup g(b) \subset g(A\cup B)

7 0
3 years ago
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