- - He runs 1.5 meters each second.
- Solve:
Divide 30/20
<span>=1.5
</span>To answer this we will divide the amount of meters by the amount of seconds. Then your answer will be the amount of meters Earl runs per second. Then we will check our work. Lets do it:-
30 ÷ 20 = 1.5
1.5 meter per second.
CHECK OUR WOK:-
1.5 × 20 = 30
<span>We were </span><span>RIGHT!!
</span><span>So, </span><span>1.5 meters per sec.</span>
Answer:the maximum number of ccf Jake can use if he wants his bill to be no more than $58.00 is $15.3
Step-by-step explanation:
Let x represent the number of ccf of water that Jake uses in a month.
Jake's water bill is $24.40 per month plus $2.20 per ccf (hundred cubic feet) of water. This means that if she uses x ccf of water in a month, her total water bill would be
24.40 + 2.2x
Therefore, the maximum number of ccf Jake can use if he wants his bill to be no more than $58.00 would be
24.40 + 2.2x ≤ 58
2.2x ≤ 58 - 24.4
2.2x ≤ 33.6
x ≤ 33.6/2.2
x ≤ 15.3
The restrictions would be possible x values that could make the function equal 0.
Answer:
the answer is a.
Step-by-step explanation:
every other answer has a y-intercept.
Answer:
x
1
Step-by-step explanation:
