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sdas [7]
3 years ago
14

find the common difference of the arithmetic sequence. 6, 9.4, 12.8, 16.2, . . . a. –1.6 b. 15.4 c. 1.6 d. 3.4

Mathematics
1 answer:
gulaghasi [49]3 years ago
5 0
<span>Common difference is just the number you pick minus the previous number,
You have </span><span>6, 9.4, 12.8, 16.2, . . .

d=9.4-6=3.4
d=12.8-9.4=3.4

The common difference is 3.4</span>
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The number of customers on the first day are (6×-3) the number of customers on the second day is (×-1) how many more customers v
EleoNora [17]

The number of customers who visited more on first day = ( 5 x - 2)

<h2>248 more people visited on the first day. </h2>

Step-by-step explanation:

The total number of customers visiting on first day  = (6 x - 3)

The total number of customers visiting on second day  = (x - 1)

The difference in the number of customers

= Number of customer visiting ( First day - Second Day)

= (6x  - 3) - (x- 1)  = 6 x - 3 - x +  1  = 5 x - 2

So, the number of customers who visited more on first day = ( 5 x - 2)

Now, when x  = 50, ( 5 x - 2) = (5 (50) - 2)  = 250 - 2  = 248

Hence, 248 more people visited on the first day.

7 0
3 years ago
Ralph says he can rewrite (4+5)+21 as 9+21. Do you agree ?why or why not?​
noname [10]
I agree because parentheses always go first and 4+5 equals 9 so in conclusion ralph is correct and the answer would be 30
4 0
3 years ago
Read 2 more answers
Help me please - ?! :C
Andrej [43]

The slope is 2.

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5 0
3 years ago
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Solve the literal equation for x<br><img src="https://tex.z-dn.net/?f=h%20%3D%207x%20-%204ux" id="TexFormula1" title="h = 7x - 4
igomit [66]

Answer: x= h/-4u+7

Step-by-step explanation:

5 0
4 years ago
the longest side of an acute isosceles triangle is 8 centimeters . rounded to the nearest tenth, what is the smallest possible l
Aleksandr-060686 [28]
<span>The smallest possible length of congruent sides of an acute isosceles triangle must be  <  than the length of congruent sides of the right isosceles triangle

so 
</span>The sides of a right isosceles triangle are in proportion: √2/2:√2/2:1

if  the longest side of an acute isosceles triangle is ----------- > 8 centimeters 
then
the smallest possible length of one of the two congruent sides
is 8*√2/2- ---------->4√2=5.66=5.6
5.6<5.66------------- is ok

we know that the two smallest sides of a triangle have to add up to be longer than the longest side.

2x>8---------- > x>4
therefore the solution is the interval (4,5.6)
the smallest possible length rounded to the nearest tenth is 4.1

the answer is 4.1
6 0
4 years ago
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