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oksano4ka [1.4K]
3 years ago
6

Jeanne babysits for 6 per hour . She also works as a reading tutor for 10 per hour . She is only allowed to work20 hours per wee

k . This week,her goal is to make at least 75
A. Use system of inequality to model the scenario above . Let x represent babysitting hours and y represent tutoring hours
B. Use the model created in part A to create a graph representing jenne’s Probable income earned and possible number hours to work this week
C. Analyze the set of coordinates values that represent solutions for the model created in par A. Choose one of the coordinates within the solution and algebraically prove that the coordinates represents a true solution for the model
Mathematics
1 answer:
mel-nik [20]3 years ago
7 0
The correct answer would be C
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Please help solve, will mark brainliest
Neko [114]

Answer:

1/3

Step-by-step explanation:

5 over 15

divide both by 5 to simplify 1 over 3

3 0
3 years ago
If (6y − 11)(6y 11) = ay^2 − b, what is the value of a? the value of a is ____________.
Triss [41]
(6y - 11)(6y + 11) = ay² - b    |use (a - b)(a + b) = a² - b²

(6y)² - 11² =ay² - b

36y² - 121 = ay² - b    |add b to both sides

ay² = 36y² - 121 + b        |divide both sides by y² ≠ 0

a = (36y² - 121 + b)/y²

\boxed{a=\dfrac{36y^2-121+b}{y^2}}
7 0
3 years ago
What sum of money amounts to rupees 545 4 at 8% BA in 30 months​
Mars2501 [29]

Answer:

let sum of money be x

amount=rupees5454

rate=8%

time=30 months

convert month into year

30/12=5/2 years

Step-by-step explanation:

interest=p*t*r/100

=x*5*8/100*2

=40x/200

=x/5

so to find principal use formula

amount=principal +interest

5454=x+x/5

5454=5x+x/5

5454*5=6x

27270/6=x

4545=x

therefore ,sum of money(principal)=rupees.4545

Hope this helps u!!

5 0
3 years ago
Jamie had 4/5 of a spool of twine. He then used 1/2 of a spool of twine to make friendship knots. Over. Explain how you know whe
Ganezh [65]

Answer:

Jamie's claims are correct because 3/10 of the spool twine is left over after using 1/2 of the spool twin for friendship knot

Step-by-step explanation:

Full question: He claims to have 3/10 of the original spool of twine leftover.

First, we compare 3/10 with 4/5 - 1/2

The lowest common multiple for2 and 5 is 10.

To write 4/5 as a fraction with common denominator, multiply numerator and denominator by 2

4/5 = (4×2)/(5×2) = 8/10

To write 1/2 as a fraction with a common denominator, multiply denominator and numerator by5

1/2 =(1×5)/(2×5) = 5/0

So we have :

8/10 - 5/10

Since denominators are equal ,we go ahead and subtract

8/10 - 5/10 = (8-5)/10 = 3/10

4 0
3 years ago
Determine a series of transformations that would map polygon ABCDE onto polygon A’B’C’D’E
zalisa [80]

Answer:

Reflected across x-axis followed by a dilation with a scale factor of 2 about the origin.

Step-by-step explanation:

It's clear from the graph,

Polygon ABCDE is reflected across x-axis then dilated so that it overlaps polygon A'B'C'D'E'

Let's choose a point A having coordinates (-2, -1)

By reflecting point A across x-axis,

Rule to be followed for the reflection,

(x, y) → (x, -y)

By this rule, coordinates of the image point A will be,

A(-2, -1) → A"(-2, 1)

Now point A"(-2, 1) has been dilated by a scale factor = k to form an image points A'(-4, 2).

Rule for the dilation of a point about the origin is,

A"(x, y) → A'(kx, ky)

A"(-2, 1) → A'(-2k, k)

Since, coordinates of point A' are (-4, -2),

Therefore, -2k = -4

k = 2

k = 2

Hence, polygon ABCDE was reflected across x-axis followed by a dilation with a scale factor of 2 about the origin to form polygon A'B'C'D'E'.

3 0
3 years ago
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