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Nadusha1986 [10]
3 years ago
11

I NEED HELP ASAP!! DUE BY 11:59 PM!!!!!!!!PLS ANSWER SOON!! PROBLEMS 27 AND 28

Mathematics
1 answer:
Arisa [49]3 years ago
4 0
Q28 the sum of odd numbers n will be
Sum=n*n
Sum off odd number 100
Sum=100*100=10000
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5x +6y = -6
nadezda [96]

Answer:

(-6,4)

Step-by-step explanation:

If this is the system of equations here is how:

solve for 1 vairuble in the first equation, and plug that it to the other.

3 0
3 years ago
3. My divisor is 8.
Vera_Pavlovna [14]

Answer: 29

Step-by-step explanation:

29 ÷ 8 = 3 remainder: 5

I solved using long division.

7 0
3 years ago
Read 2 more answers
6 out of 9 pairs of your jeans are blue. What percentage of you<br>jeans are NOT blue?​
Tema [17]

Answer:

33.333333%

Step-by-step explanation:

If 6/9 (66.66666666%) of the jeans are blue it means that 3/9 of the jeans are not blue. 3/9 as a percentage is 33.333333%

8 0
3 years ago
Read 2 more answers
A amusement park charges $35.50 for admission. On Saturday, 3,247 people visited the park. On Sunday, 3,542 people visited the p
garik1379 [7]

Answer:

$241009.50

Step-by-step explanation:

35.50*3247=115268.50

35.50*3542=125741.00

                   +________

                     241009.5

6 0
3 years ago
A national study report indicated that​ 20.9% of Americans were identified as having medical bill financial issues. What if a ne
Alenkasestr [34]

Answer:

The​ p-value for this​ test is 0.22065.

Step-by-step explanation:

We are given that a national study report indicated that​ 20.9% of Americans were identified as having medical bill financial issues.

A news organization randomly sampled 400 Americans from 10 cities and found that 90 reported having such difficulty.

<u><em>Let p = proportion of Americans who were identified as having medical bill financial issues in 10 cities.</em></u>

SO, Null Hypothesis, H_0 : p \leq 20.9%   {means that % of Americans who were identified as having medical bill financial issues in these 10 cities is less than or equal to 20.9%}

Alternate Hypothesis, H_A : p > 20.9%   {means that % of Americans who were identified as having medical bill financial issues in these 10 cities is more than 20.9% and is more severe}

The test statistics that will be used here is <u>One-sample z proportion</u> <u>statistics</u>;

                                  T.S.  = \frac{\hat p-p}{{\sqrt{\frac{\hat p(1-\hat p)}{n} } } } }  ~ N(0,1)

where, \hat p = sample proportion of 400 Americans from 10 cities who were found having such difficulty =  \frac{90}{400} = 0.225 or 22.5%

            n = sample of Americans = 400

So, <u><em>test statistics</em></u>  =  \frac{0.225-0.209}{{\sqrt{\frac{0.225(1-0.225)}{400} } } } }

                               =  0.77

<u></u>

<u>Now, P-value of the test statistics is given by the following formula;</u>

         P-value = P(Z > 0.77) = 1 - P(Z \leq 0.77)

                                            = 1 - 0.77935 = 0.22065

5 0
3 years ago
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